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686 lines
22 KiB
Markdown
686 lines
22 KiB
Markdown
---
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comments: true
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---
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# 7.1 Binary tree
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A "binary tree" is a non-linear data structure that represents the ancestral and descendent relationships, embodying the "divide and conquer" logic. Similar to a linked list, the basic unit of a binary tree is a node, each containing a value, a reference to the left child node, and a reference to the right child node.
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=== "Python"
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```python title=""
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class TreeNode:
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"""Binary tree node"""
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def __init__(self, val: int):
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self.val: int = val # Node value
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self.left: TreeNode | None = None # Reference to left child node
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self.right: TreeNode | None = None # Reference to right child node
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```
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=== "C++"
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```cpp title=""
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/* Binary tree node */
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struct TreeNode {
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int val; // Node value
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TreeNode *left; // Pointer to left child node
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TreeNode *right; // Pointer to right child node
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TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
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};
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```
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=== "Java"
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```java title=""
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/* Binary tree node */
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class TreeNode {
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int val; // Node value
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TreeNode left; // Reference to left child node
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TreeNode right; // Reference to right child node
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TreeNode(int x) { val = x; }
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}
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```
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=== "C#"
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```csharp title=""
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/* Binary tree node */
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class TreeNode(int? x) {
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public int? val = x; // Node value
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public TreeNode? left; // Reference to left child node
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public TreeNode? right; // Reference to right child node
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}
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```
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=== "Go"
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```go title=""
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/* Binary tree node */
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type TreeNode struct {
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Val int
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Left *TreeNode
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Right *TreeNode
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}
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/* 构造方法 */
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func NewTreeNode(v int) *TreeNode {
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return &TreeNode{
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Left: nil, // Pointer to left child node
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Right: nil, // Pointer to right child node
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Val: v, // Node value
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}
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}
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```
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=== "Swift"
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```swift title=""
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/* Binary tree node */
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class TreeNode {
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var val: Int // Node value
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var left: TreeNode? // Reference to left child node
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var right: TreeNode? // Reference to right child node
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init(x: Int) {
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val = x
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}
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}
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```
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=== "JS"
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```javascript title=""
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/* Binary tree node */
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class TreeNode {
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val; // Node value
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left; // Pointer to left child node
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right; // Pointer to right child node
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constructor(val, left, right) {
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this.val = val === undefined ? 0 : val;
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this.left = left === undefined ? null : left;
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this.right = right === undefined ? null : right;
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}
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}
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```
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=== "TS"
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```typescript title=""
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/* Binary tree node */
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class TreeNode {
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val: number;
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left: TreeNode | null;
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right: TreeNode | null;
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constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
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this.val = val === undefined ? 0 : val; // Node value
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this.left = left === undefined ? null : left; // Reference to left child node
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this.right = right === undefined ? null : right; // Reference to right child node
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}
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}
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```
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=== "Dart"
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```dart title=""
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/* Binary tree node */
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class TreeNode {
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int val; // Node value
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TreeNode? left; // Reference to left child node
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TreeNode? right; // Reference to right child node
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TreeNode(this.val, [this.left, this.right]);
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}
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```
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=== "Rust"
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```rust title=""
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use std::rc::Rc;
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use std::cell::RefCell;
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/* Binary tree node */
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struct TreeNode {
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val: i32, // Node value
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left: Option<Rc<RefCell<TreeNode>>>, // Reference to left child node
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right: Option<Rc<RefCell<TreeNode>>>, // Reference to right child node
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}
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impl TreeNode {
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/* 构造方法 */
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fn new(val: i32) -> Rc<RefCell<Self>> {
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Rc::new(RefCell::new(Self {
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val,
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left: None,
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right: None
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}))
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}
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}
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```
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=== "C"
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```c title=""
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/* Binary tree node */
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typedef struct TreeNode {
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int val; // Node value
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int height; // 节点高度
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struct TreeNode *left; // Pointer to left child node
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struct TreeNode *right; // Pointer to right child node
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} TreeNode;
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/* 构造函数 */
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TreeNode *newTreeNode(int val) {
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TreeNode *node;
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node = (TreeNode *)malloc(sizeof(TreeNode));
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node->val = val;
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node->height = 0;
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node->left = NULL;
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node->right = NULL;
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return node;
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}
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```
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=== "Kotlin"
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```kotlin title=""
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/* Binary tree node */
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class TreeNode(val _val: Int) { // Node value
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val left: TreeNode? = null // Reference to left child node
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val right: TreeNode? = null // Reference to right child node
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}
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```
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=== "Ruby"
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```ruby title=""
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```
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=== "Zig"
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```zig title=""
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```
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Each node has two references (pointers), pointing to the "left-child node" and "right-child node," respectively. This node is called the "parent node" of these two child nodes. When given a node of a binary tree, we call the tree formed by this node's left child and all nodes under it the "left subtree" of this node. Similarly, the "right subtree" can be defined.
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**In a binary tree, except for leaf nodes, all other nodes contain child nodes and non-empty subtrees.** As shown in Figure 7-1, if "Node 2" is considered as the parent node, then its left and right child nodes are "Node 4" and "Node 5," respectively. The left subtree is "the tree formed by Node 4 and all nodes under it," and the right subtree is "the tree formed by Node 5 and all nodes under it."
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![Parent Node, child Node, subtree](binary_tree.assets/binary_tree_definition.png){ class="animation-figure" }
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<p align="center"> Figure 7-1 Parent Node, child Node, subtree </p>
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## 7.1.1 Common terminology of binary trees
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The commonly used terminology of binary trees is shown in Figure 7-2.
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- "Root node": The node at the top level of the binary tree, which has no parent node.
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- "Leaf node": A node with no children, both of its pointers point to `None`.
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- "Edge": The line segment connecting two nodes, i.e., node reference (pointer).
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- The "level" of a node: Incrementing from top to bottom, with the root node's level being 1.
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- The "degree" of a node: The number of a node's children. In a binary tree, the degree can be 0, 1, or 2.
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- The "height" of a binary tree: The number of edges passed from the root node to the farthest leaf node.
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- The "depth" of a node: The number of edges passed from the root node to the node.
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- The "height" of a node: The number of edges from the farthest leaf node to the node.
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![Common Terminology of Binary Trees](binary_tree.assets/binary_tree_terminology.png){ class="animation-figure" }
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<p align="center"> Figure 7-2 Common Terminology of Binary Trees </p>
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!!! tip
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Please note that we usually define "height" and "depth" as "the number of edges passed," but some problems or textbooks may define them as "the number of nodes passed." In this case, both height and depth need to be incremented by 1.
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## 7.1.2 Basic operations of binary trees
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### 1. Initializing a binary tree
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Similar to a linked list, initialize nodes first, then construct references (pointers).
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=== "Python"
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```python title="binary_tree.py"
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# Initializing a binary tree
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# Initializing nodes
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n1 = TreeNode(val=1)
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n2 = TreeNode(val=2)
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n3 = TreeNode(val=3)
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n4 = TreeNode(val=4)
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n5 = TreeNode(val=5)
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# Linking references (pointers) between nodes
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n1.left = n2
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n1.right = n3
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n2.left = n4
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n2.right = n5
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```
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=== "C++"
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```cpp title="binary_tree.cpp"
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/* Initializing a binary tree */
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// Initializing nodes
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TreeNode* n1 = new TreeNode(1);
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TreeNode* n2 = new TreeNode(2);
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TreeNode* n3 = new TreeNode(3);
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TreeNode* n4 = new TreeNode(4);
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TreeNode* n5 = new TreeNode(5);
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// Linking references (pointers) between nodes
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n1->left = n2;
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n1->right = n3;
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n2->left = n4;
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n2->right = n5;
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```
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=== "Java"
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```java title="binary_tree.java"
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// Initializing nodes
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TreeNode n1 = new TreeNode(1);
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TreeNode n2 = new TreeNode(2);
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TreeNode n3 = new TreeNode(3);
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TreeNode n4 = new TreeNode(4);
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TreeNode n5 = new TreeNode(5);
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// Linking references (pointers) between nodes
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n1.left = n2;
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n1.right = n3;
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n2.left = n4;
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n2.right = n5;
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```
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=== "C#"
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```csharp title="binary_tree.cs"
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/* Initializing a binary tree */
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// Initializing nodes
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TreeNode n1 = new(1);
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TreeNode n2 = new(2);
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TreeNode n3 = new(3);
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TreeNode n4 = new(4);
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TreeNode n5 = new(5);
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// Linking references (pointers) between nodes
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n1.left = n2;
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n1.right = n3;
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n2.left = n4;
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n2.right = n5;
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```
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=== "Go"
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```go title="binary_tree.go"
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/* Initializing a binary tree */
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// Initializing nodes
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n1 := NewTreeNode(1)
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n2 := NewTreeNode(2)
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n3 := NewTreeNode(3)
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n4 := NewTreeNode(4)
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n5 := NewTreeNode(5)
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// Linking references (pointers) between nodes
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n1.Left = n2
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n1.Right = n3
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n2.Left = n4
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n2.Right = n5
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```
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=== "Swift"
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```swift title="binary_tree.swift"
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// Initializing nodes
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let n1 = TreeNode(x: 1)
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let n2 = TreeNode(x: 2)
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let n3 = TreeNode(x: 3)
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let n4 = TreeNode(x: 4)
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let n5 = TreeNode(x: 5)
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// Linking references (pointers) between nodes
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n1.left = n2
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n1.right = n3
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n2.left = n4
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n2.right = n5
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```
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=== "JS"
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```javascript title="binary_tree.js"
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/* Initializing a binary tree */
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// Initializing nodes
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let n1 = new TreeNode(1),
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n2 = new TreeNode(2),
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n3 = new TreeNode(3),
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n4 = new TreeNode(4),
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n5 = new TreeNode(5);
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// Linking references (pointers) between nodes
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n1.left = n2;
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n1.right = n3;
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n2.left = n4;
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n2.right = n5;
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```
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=== "TS"
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```typescript title="binary_tree.ts"
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/* Initializing a binary tree */
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// Initializing nodes
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let n1 = new TreeNode(1),
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n2 = new TreeNode(2),
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n3 = new TreeNode(3),
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n4 = new TreeNode(4),
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n5 = new TreeNode(5);
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// Linking references (pointers) between nodes
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n1.left = n2;
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n1.right = n3;
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n2.left = n4;
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n2.right = n5;
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```
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=== "Dart"
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```dart title="binary_tree.dart"
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/* Initializing a binary tree */
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// Initializing nodes
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TreeNode n1 = new TreeNode(1);
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TreeNode n2 = new TreeNode(2);
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TreeNode n3 = new TreeNode(3);
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TreeNode n4 = new TreeNode(4);
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TreeNode n5 = new TreeNode(5);
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// Linking references (pointers) between nodes
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n1.left = n2;
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n1.right = n3;
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n2.left = n4;
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n2.right = n5;
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```
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=== "Rust"
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```rust title="binary_tree.rs"
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// Initializing nodes
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let n1 = TreeNode::new(1);
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let n2 = TreeNode::new(2);
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let n3 = TreeNode::new(3);
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let n4 = TreeNode::new(4);
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let n5 = TreeNode::new(5);
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// Linking references (pointers) between nodes
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n1.borrow_mut().left = Some(n2.clone());
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n1.borrow_mut().right = Some(n3);
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n2.borrow_mut().left = Some(n4);
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n2.borrow_mut().right = Some(n5);
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```
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=== "C"
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```c title="binary_tree.c"
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/* Initializing a binary tree */
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// Initializing nodes
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TreeNode *n1 = newTreeNode(1);
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TreeNode *n2 = newTreeNode(2);
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TreeNode *n3 = newTreeNode(3);
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TreeNode *n4 = newTreeNode(4);
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TreeNode *n5 = newTreeNode(5);
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// Linking references (pointers) between nodes
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n1->left = n2;
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n1->right = n3;
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n2->left = n4;
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n2->right = n5;
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```
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=== "Kotlin"
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```kotlin title="binary_tree.kt"
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// Initializing nodes
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val n1 = TreeNode(1)
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val n2 = TreeNode(2)
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val n3 = TreeNode(3)
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val n4 = TreeNode(4)
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val n5 = TreeNode(5)
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// Linking references (pointers) between nodes
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n1.left = n2
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n1.right = n3
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n2.left = n4
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n2.right = n5
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```
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=== "Ruby"
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```ruby title="binary_tree.rb"
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```
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=== "Zig"
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```zig title="binary_tree.zig"
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```
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??? pythontutor "Code visualization"
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https://pythontutor.com/render.html#code=class%20TreeNode%3A%0A%20%20%20%20%22%22%22%E4%BA%8C%E5%8F%89%E6%A0%91%E8%8A%82%E7%82%B9%E7%B1%BB%22%22%22%0A%20%20%20%20def%20__init__%28self,%20val%3A%20int%29%3A%0A%20%20%20%20%20%20%20%20self.val%3A%20int%20%3D%20val%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%23%20%E8%8A%82%E7%82%B9%E5%80%BC%0A%20%20%20%20%20%20%20%20self.left%3A%20TreeNode%20%7C%20None%20%3D%20None%20%20%23%20%E5%B7%A6%E5%AD%90%E8%8A%82%E7%82%B9%E5%BC%95%E7%94%A8%0A%20%20%20%20%20%20%20%20self.right%3A%20TreeNode%20%7C%20None%20%3D%20None%20%23%20%E5%8F%B3%E5%AD%90%E8%8A%82%E7%82%B9%E5%BC%95%E7%94%A8%0A%0A%22%22%22Driver%20Code%22%22%22%0Aif%20__name__%20%3D%3D%20%22__main__%22%3A%0A%20%20%20%20%23%20%E5%88%9D%E5%A7%8B%E5%8C%96%E4%BA%8C%E5%8F%89%E6%A0%91%0A%20%20%20%20%23%20%E5%88%9D%E5%A7%8B%E5%8C%96%E8%8A%82%E7%82%B9%0A%20%20%20%20n1%20%3D%20TreeNode%28val%3D1%29%0A%20%20%20%20n2%20%3D%20TreeNode%28val%3D2%29%0A%20%20%20%20n3%20%3D%20TreeNode%28val%3D3%29%0A%20%20%20%20n4%20%3D%20TreeNode%28val%3D4%29%0A%20%20%20%20n5%20%3D%20TreeNode%28val%3D5%29%0A%20%20%20%20%23%20%E6%9E%84%E5%BB%BA%E8%8A%82%E7%82%B9%E4%B9%8B%E9%97%B4%E7%9A%84%E5%BC%95%E7%94%A8%EF%BC%88%E6%8C%87%E9%92%88%EF%BC%89%0A%20%20%20%20n1.left%20%3D%20n2%0A%20%20%20%20n1.right%20%3D%20n3%0A%20%20%20%20n2.left%20%3D%20n4%0A%20%20%20%20n2.right%20%3D%20n5&cumulative=false&curInstr=3&heapPrimitives=nevernest&mode=display&origin=opt-frontend.js&py=311&rawInputLstJSON=%5B%5D&textReferences=false
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### 2. Inserting and removing nodes
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Similar to a linked list, inserting and removing nodes in a binary tree can be achieved by modifying pointers. Figure 7-3 provides an example.
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![Inserting and removing nodes in a binary tree](binary_tree.assets/binary_tree_add_remove.png){ class="animation-figure" }
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<p align="center"> Figure 7-3 Inserting and removing nodes in a binary tree </p>
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=== "Python"
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```python title="binary_tree.py"
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# Inserting and removing nodes
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p = TreeNode(0)
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# Inserting node P between n1 -> n2
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n1.left = p
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p.left = n2
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# Removing node P
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n1.left = n2
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```
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=== "C++"
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```cpp title="binary_tree.cpp"
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/* Inserting and removing nodes */
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TreeNode* P = new TreeNode(0);
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// Inserting node P between n1 and n2
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n1->left = P;
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P->left = n2;
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// Removing node P
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n1->left = n2;
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```
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=== "Java"
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|
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```java title="binary_tree.java"
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TreeNode P = new TreeNode(0);
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// Inserting node P between n1 and n2
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n1.left = P;
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P.left = n2;
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// Removing node P
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n1.left = n2;
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|
```
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=== "C#"
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```csharp title="binary_tree.cs"
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/* Inserting and removing nodes */
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TreeNode P = new(0);
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// Inserting node P between n1 and n2
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n1.left = P;
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P.left = n2;
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// Removing node P
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n1.left = n2;
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```
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=== "Go"
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```go title="binary_tree.go"
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/* Inserting and removing nodes */
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// Inserting node P between n1 and n2
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p := NewTreeNode(0)
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n1.Left = p
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p.Left = n2
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// Removing node P
|
|
n1.Left = n2
|
|
```
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|
=== "Swift"
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```swift title="binary_tree.swift"
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let P = TreeNode(x: 0)
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// Inserting node P between n1 and n2
|
|
n1.left = P
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|
P.left = n2
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|
// Removing node P
|
|
n1.left = n2
|
|
```
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|
=== "JS"
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|
|
|
```javascript title="binary_tree.js"
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/* Inserting and removing nodes */
|
|
let P = new TreeNode(0);
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|
// Inserting node P between n1 and n2
|
|
n1.left = P;
|
|
P.left = n2;
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|
// Removing node P
|
|
n1.left = n2;
|
|
```
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|
|
=== "TS"
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|
|
|
```typescript title="binary_tree.ts"
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|
/* Inserting and removing nodes */
|
|
const P = new TreeNode(0);
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|
// Inserting node P between n1 and n2
|
|
n1.left = P;
|
|
P.left = n2;
|
|
// Removing node P
|
|
n1.left = n2;
|
|
```
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|
|
|
=== "Dart"
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|
|
|
```dart title="binary_tree.dart"
|
|
/* Inserting and removing nodes */
|
|
TreeNode P = new TreeNode(0);
|
|
// Inserting node P between n1 and n2
|
|
n1.left = P;
|
|
P.left = n2;
|
|
// Removing node P
|
|
n1.left = n2;
|
|
```
|
|
|
|
=== "Rust"
|
|
|
|
```rust title="binary_tree.rs"
|
|
let p = TreeNode::new(0);
|
|
// Inserting node P between n1 and n2
|
|
n1.borrow_mut().left = Some(p.clone());
|
|
p.borrow_mut().left = Some(n2.clone());
|
|
// Removing node P
|
|
n1.borrow_mut().left = Some(n2);
|
|
```
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|
|
|
=== "C"
|
|
|
|
```c title="binary_tree.c"
|
|
/* Inserting and removing nodes */
|
|
TreeNode *P = newTreeNode(0);
|
|
// Inserting node P between n1 and n2
|
|
n1->left = P;
|
|
P->left = n2;
|
|
// Removing node P
|
|
n1->left = n2;
|
|
```
|
|
|
|
=== "Kotlin"
|
|
|
|
```kotlin title="binary_tree.kt"
|
|
val P = TreeNode(0)
|
|
// Inserting node P between n1 and n2
|
|
n1.left = P
|
|
P.left = n2
|
|
// Removing node P
|
|
n1.left = n2
|
|
```
|
|
|
|
=== "Ruby"
|
|
|
|
```ruby title="binary_tree.rb"
|
|
|
|
```
|
|
|
|
=== "Zig"
|
|
|
|
```zig title="binary_tree.zig"
|
|
|
|
```
|
|
|
|
??? pythontutor "Code visualization"
|
|
|
|
https://pythontutor.com/render.html#code=class%20TreeNode%3A%0A%20%20%20%20%22%22%22%E4%BA%8C%E5%8F%89%E6%A0%91%E8%8A%82%E7%82%B9%E7%B1%BB%22%22%22%0A%20%20%20%20def%20__init__%28self,%20val%3A%20int%29%3A%0A%20%20%20%20%20%20%20%20self.val%3A%20int%20%3D%20val%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%23%20%E8%8A%82%E7%82%B9%E5%80%BC%0A%20%20%20%20%20%20%20%20self.left%3A%20TreeNode%20%7C%20None%20%3D%20None%20%20%23%20%E5%B7%A6%E5%AD%90%E8%8A%82%E7%82%B9%E5%BC%95%E7%94%A8%0A%20%20%20%20%20%20%20%20self.right%3A%20TreeNode%20%7C%20None%20%3D%20None%20%23%20%E5%8F%B3%E5%AD%90%E8%8A%82%E7%82%B9%E5%BC%95%E7%94%A8%0A%0A%22%22%22Driver%20Code%22%22%22%0Aif%20__name__%20%3D%3D%20%22__main__%22%3A%0A%20%20%20%20%23%20%E5%88%9D%E5%A7%8B%E5%8C%96%E4%BA%8C%E5%8F%89%E6%A0%91%0A%20%20%20%20%23%20%E5%88%9D%E5%A7%8B%E5%8C%96%E8%8A%82%E7%82%B9%0A%20%20%20%20n1%20%3D%20TreeNode%28val%3D1%29%0A%20%20%20%20n2%20%3D%20TreeNode%28val%3D2%29%0A%20%20%20%20n3%20%3D%20TreeNode%28val%3D3%29%0A%20%20%20%20n4%20%3D%20TreeNode%28val%3D4%29%0A%20%20%20%20n5%20%3D%20TreeNode%28val%3D5%29%0A%20%20%20%20%23%20%E6%9E%84%E5%BB%BA%E8%8A%82%E7%82%B9%E4%B9%8B%E9%97%B4%E7%9A%84%E5%BC%95%E7%94%A8%EF%BC%88%E6%8C%87%E9%92%88%EF%BC%89%0A%20%20%20%20n1.left%20%3D%20n2%0A%20%20%20%20n1.right%20%3D%20n3%0A%20%20%20%20n2.left%20%3D%20n4%0A%20%20%20%20n2.right%20%3D%20n5%0A%0A%20%20%20%20%23%20%E6%8F%92%E5%85%A5%E4%B8%8E%E5%88%A0%E9%99%A4%E8%8A%82%E7%82%B9%0A%20%20%20%20p%20%3D%20TreeNode%280%29%0A%20%20%20%20%23%20%E5%9C%A8%20n1%20-%3E%20n2%20%E4%B8%AD%E9%97%B4%E6%8F%92%E5%85%A5%E8%8A%82%E7%82%B9%20P%0A%20%20%20%20n1.left%20%3D%20p%0A%20%20%20%20p.left%20%3D%20n2%0A%20%20%20%20%23%20%E5%88%A0%E9%99%A4%E8%8A%82%E7%82%B9%20P%0A%20%20%20%20n1.left%20%3D%20n2&cumulative=false&curInstr=37&heapPrimitives=nevernest&mode=display&origin=opt-frontend.js&py=311&rawInputLstJSON=%5B%5D&textReferences=false
|
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|
|
!!! tip
|
|
|
|
It's important to note that inserting nodes may change the original logical structure of the binary tree, while removing nodes usually means removing the node and all its subtrees. Therefore, in a binary tree, insertion and removal are usually performed through a set of operations to achieve meaningful actions.
|
|
|
|
## 7.1.3 Common types of binary trees
|
|
|
|
### 1. Perfect binary tree
|
|
|
|
As shown in Figure 7-4, in a "perfect binary tree," all levels of nodes are fully filled. In a perfect binary tree, the degree of leaf nodes is $0$, and the degree of all other nodes is $2$; if the tree's height is $h$, then the total number of nodes is $2^{h+1} - 1$, showing a standard exponential relationship, reflecting the common phenomenon of cell division in nature.
|
|
|
|
!!! tip
|
|
|
|
Please note that in the Chinese community, a perfect binary tree is often referred to as a "full binary tree."
|
|
|
|
![Perfect binary tree](binary_tree.assets/perfect_binary_tree.png){ class="animation-figure" }
|
|
|
|
<p align="center"> Figure 7-4 Perfect binary tree </p>
|
|
|
|
### 2. Complete binary tree
|
|
|
|
As shown in Figure 7-5, a "complete binary tree" has only the bottom level nodes not fully filled, and the bottom level nodes are filled as far left as possible.
|
|
|
|
![Complete binary tree](binary_tree.assets/complete_binary_tree.png){ class="animation-figure" }
|
|
|
|
<p align="center"> Figure 7-5 Complete binary tree </p>
|
|
|
|
### 3. Full binary tree
|
|
|
|
As shown in Figure 7-6, a "full binary tree" has all nodes except leaf nodes having two children.
|
|
|
|
![Full binary tree](binary_tree.assets/full_binary_tree.png){ class="animation-figure" }
|
|
|
|
<p align="center"> Figure 7-6 Full binary tree </p>
|
|
|
|
### 4. Balanced binary tree
|
|
|
|
As shown in Figure 7-7, in a "balanced binary tree," the absolute difference in height between the left and right subtrees of any node does not exceed 1.
|
|
|
|
![Balanced binary tree](binary_tree.assets/balanced_binary_tree.png){ class="animation-figure" }
|
|
|
|
<p align="center"> Figure 7-7 Balanced binary tree </p>
|
|
|
|
## 7.1.4 Degeneration of binary trees
|
|
|
|
Figure 7-8 shows the ideal and degenerate structures of binary trees. When every level of a binary tree is filled, it reaches the "perfect binary tree"; when all nodes are biased towards one side, the binary tree degenerates into a "linked list".
|
|
|
|
- The perfect binary tree is the ideal situation, fully leveraging the "divide and conquer" advantage of binary trees.
|
|
- A linked list is another extreme, where operations become linear, degrading the time complexity to $O(n)$.
|
|
|
|
![The Best and Worst Structures of Binary Trees](binary_tree.assets/binary_tree_best_worst_cases.png){ class="animation-figure" }
|
|
|
|
<p align="center"> Figure 7-8 The Best and Worst Structures of Binary Trees </p>
|
|
|
|
As shown in Table 7-1, in the best and worst structures, the number of leaf nodes, total number of nodes, and height of the binary tree reach their maximum or minimum values.
|
|
|
|
<p align="center"> Table 7-1 The Best and Worst Structures of Binary Trees </p>
|
|
|
|
<div class="center-table" markdown>
|
|
|
|
| | Perfect binary tree | Linked list |
|
|
| ----------------------------------------------- | ------------------- | ----------- |
|
|
| Number of nodes at level $i$ | $2^{i-1}$ | $1$ |
|
|
| Number of leaf nodes in a tree with height $h$ | $2^h$ | $1$ |
|
|
| Total number of nodes in a tree with height $h$ | $2^{h+1} - 1$ | $h + 1$ |
|
|
| Height of a tree with $n$ total nodes | $\log_2 (n+1) - 1$ | $n - 1$ |
|
|
|
|
</div>
|