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https://github.com/krahets/hello-algo.git
synced 2024-12-26 00:26:29 +08:00
build
This commit is contained in:
krahets
parent
d5a7899137
commit
0a9daa8b9f
11 changed files with 685 additions and 97 deletions
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@ -314,7 +314,7 @@ comments: true
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### 随机访问元素 ###
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def random_access(nums)
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# 在区间 [0, nums.length) 中随机抽取一个数字
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random_index = Random.rand 0...(nums.length - 1)
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random_index = Random.rand(0...nums.length)
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# 获取并返回随机元素
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nums[random_index]
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@ -427,11 +427,11 @@ comments: true
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```ruby title="linked_list.rb"
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# 初始化链表 1 -> 3 -> 2 -> 5 -> 4
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# 初始化各个节点
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n0 = ListNode.new 1
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n1 = ListNode.new 3
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n2 = ListNode.new 2
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n3 = ListNode.new 5
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n4 = ListNode.new 4
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n0 = ListNode.new(1)
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n1 = ListNode.new(3)
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n2 = ListNode.new(2)
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n3 = ListNode.new(5)
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n4 = ListNode.new(4)
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# 构建节点之间的引用
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n0.next = n1
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n1.next = n2
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@ -551,10 +551,10 @@ comments: true
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nums << 4
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# 在中间插入元素
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nums.insert 3, 6 # 在索引 3 处插入数字 6
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nums.insert(3, 6) # 在索引 3 处插入数字 6
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# 删除元素
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nums.delete_at 3 # 删除索引 3 处的元素
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nums.delete_at(3) # 删除索引 3 处的元素
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```
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=== "Zig"
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@ -2288,7 +2288,7 @@ comments: true
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@capacity = 10
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@size = 0
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@extend_ratio = 2
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@arr = Array.new capacity
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@arr = Array.new(capacity)
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end
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### 访问元素 ###
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@ -2360,9 +2360,9 @@ comments: true
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def to_array
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sz = size
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# 仅转换有效长度范围内的列表元素
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arr = Array.new sz
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arr = Array.new(sz)
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for i in 0...sz
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arr[i] = get i
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arr[i] = get(i)
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end
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arr
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end
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@ -185,7 +185,17 @@ comments: true
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=== "Ruby"
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```ruby title="iteration.rb"
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[class]{}-[func]{for_loop}
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### for 循环 ###
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def for_loop(n)
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res = 0
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# 循环求和 1, 2, ..., n-1, n
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for i in 1..n
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res += i
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end
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res
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end
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```
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=== "Zig"
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@ -417,7 +427,19 @@ comments: true
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=== "Ruby"
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```ruby title="iteration.rb"
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[class]{}-[func]{while_loop}
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### while 循环 ###
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def while_loop(n)
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res = 0
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i = 1 # 初始化条件变量
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# 循环求和 1, 2, ..., n-1, n
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while i <= n
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res += i
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i += 1 # 更新条件变量
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end
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res
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end
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```
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=== "Zig"
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@ -664,7 +686,21 @@ comments: true
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=== "Ruby"
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```ruby title="iteration.rb"
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[class]{}-[func]{while_loop_ii}
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### while 循环（两次更新）###
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def while_loop_ii(n)
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res = 0
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i = 1 # 初始化条件变量
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# 循环求和 1, 4, 10, ...
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while i <= n
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res += i
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# 更新条件变量
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i += 1
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i *= 2
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end
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res
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end
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```
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=== "Zig"
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@ -904,7 +940,20 @@ comments: true
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=== "Ruby"
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```ruby title="iteration.rb"
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[class]{}-[func]{nested_for_loop}
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### 双层 for 循环 ###
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def nested_for_loop(n)
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res = ""
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# 循环 i = 1, 2, ..., n-1, n
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for i in 1..n
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# 循环 j = 1, 2, ..., n-1, n
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for j in 1..n
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res += "(#{i}, #{j}), "
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end
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end
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res
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end
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```
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=== "Zig"
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@ -1139,7 +1188,15 @@ comments: true
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=== "Ruby"
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```ruby title="recursion.rb"
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[class]{}-[func]{recur}
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### 递归 ###
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def recur(n)
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# 终止条件
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return 1 if n == 1
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# 递：递归调用
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res = recur(n - 1)
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# 归：返回结果
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n + res
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end
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```
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=== "Zig"
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@ -1362,7 +1419,13 @@ comments: true
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=== "Ruby"
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```ruby title="recursion.rb"
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[class]{}-[func]{tail_recur}
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### 尾递归 ###
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def tail_recur(n, res)
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# 终止条件
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return res if n == 0
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# 尾递归调用
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tail_recur(n - 1, res + n)
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end
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```
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=== "Zig"
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@ -1594,7 +1657,15 @@ comments: true
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=== "Ruby"
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```ruby title="recursion.rb"
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[class]{}-[func]{fib}
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### 斐波那契数列：递归 ###
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def fib(n)
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# 终止条件 f(1) = 0, f(2) = 1
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return n - 1 if n == 1 || n == 2
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# 递归调用 f(n) = f(n-1) + f(n-2)
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res = fib(n - 1) + fib(n - 2)
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# 返回结果 f(n)
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res
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end
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```
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=== "Zig"
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@ -1936,7 +2007,25 @@ comments: true
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=== "Ruby"
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```ruby title="recursion.rb"
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[class]{}-[func]{for_loop_recur}
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### 使用迭代模拟递归 ###
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def for_loop_recur(n)
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# 使用一个显式的栈来模拟系统调用栈
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stack = []
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res = 0
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# 递：递归调用
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for i in n.downto(0)
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# 通过“入栈操作”模拟“递”
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stack << i
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end
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# 归：返回结果
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while !stack.empty?
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res += stack.pop
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end
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# res = 1+2+3+...+n
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res
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end
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```
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=== "Zig"
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@ -341,7 +341,30 @@ comments: true
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=== "Ruby"
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```ruby title=""
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### 类 ###
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class Node
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attr_accessor :val # 节点值
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attr_accessor :next # 指向下一节点的引用
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def initialize(x)
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@val = x
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end
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end
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### 函数 ###
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def function
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# 执行某些操作...
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0
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end
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### 算法 ###
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def algorithm(n) # 输入数据
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a = 0 # 暂存数据（常量）
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b = 0 # 暂存数据（变量）
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node = Node.new(0) # 暂存数据（对象）
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c = function # 栈帧空间（调用函数）
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a + b + c # 输出数据
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end
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```
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=== "Zig"
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@ -505,7 +528,11 @@ comments: true
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=== "Ruby"
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```ruby title=""
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def algorithm(n)
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a = 0 # O(1)
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b = Array.new(10000) # O(1)
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nums = Array.new(n) if n > 10 # O(n)
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end
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```
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=== "Zig"
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@ -542,13 +569,13 @@ comments: true
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// 执行某些操作
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return 0;
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}
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/* 循环 O(1) */
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/* 循环的空间复杂度为 O(1) */
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void loop(int n) {
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for (int i = 0; i < n; i++) {
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func();
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}
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}
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/* 递归 O(n) */
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/* 递归的空间复杂度为 O(n) */
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void recur(int n) {
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if (n == 1) return;
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return recur(n - 1);
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@ -562,13 +589,13 @@ comments: true
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// 执行某些操作
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return 0;
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}
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/* 循环 O(1) */
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/* 循环的空间复杂度为 O(1) */
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void loop(int n) {
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for (int i = 0; i < n; i++) {
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function();
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}
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}
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/* 递归 O(n) */
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/* 递归的空间复杂度为 O(n) */
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void recur(int n) {
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if (n == 1) return;
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return recur(n - 1);
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@ -582,13 +609,13 @@ comments: true
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// 执行某些操作
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return 0;
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}
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/* 循环 O(1) */
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/* 循环的空间复杂度为 O(1) */
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void Loop(int n) {
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for (int i = 0; i < n; i++) {
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Function();
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}
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}
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/* 递归 O(n) */
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/* 递归的空间复杂度为 O(n) */
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int Recur(int n) {
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if (n == 1) return 1;
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return Recur(n - 1);
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@ -603,14 +630,14 @@ comments: true
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return 0
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}
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/* 循环 O(1) */
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/* 循环的空间复杂度为 O(1) */
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func loop(n int) {
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for i := 0; i < n; i++ {
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function()
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}
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}
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/* 递归 O(n) */
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/* 递归的空间复杂度为 O(n) */
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func recur(n int) {
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if n == 1 {
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return
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|
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@ -628,14 +655,14 @@ comments: true
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return 0
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}
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/* 循环 O(1) */
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/* 循环的空间复杂度为 O(1) */
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func loop(n: Int) {
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for _ in 0 ..< n {
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function()
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}
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}
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|
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/* 递归 O(n) */
|
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/* 递归的空间复杂度为 O(n) */
|
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func recur(n: Int) {
|
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if n == 1 {
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return
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|
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@ -651,13 +678,13 @@ comments: true
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// 执行某些操作
|
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return 0;
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}
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/* 循环 O(1) */
|
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/* 循环的空间复杂度为 O(1) */
|
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function loop(n) {
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for (let i = 0; i < n; i++) {
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constFunc();
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}
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}
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/* 递归 O(n) */
|
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/* 递归的空间复杂度为 O(n) */
|
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function recur(n) {
|
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if (n === 1) return;
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return recur(n - 1);
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|
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@ -671,13 +698,13 @@ comments: true
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// 执行某些操作
|
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return 0;
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}
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/* 循环 O(1) */
|
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/* 循环的空间复杂度为 O(1) */
|
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function loop(n: number): void {
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for (let i = 0; i < n; i++) {
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constFunc();
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}
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}
|
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/* 递归 O(n) */
|
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/* 递归的空间复杂度为 O(n) */
|
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function recur(n: number): void {
|
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if (n === 1) return;
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return recur(n - 1);
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|
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@ -691,13 +718,13 @@ comments: true
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// 执行某些操作
|
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return 0;
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}
|
||||
/* 循环 O(1) */
|
||||
/* 循环的空间复杂度为 O(1) */
|
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void loop(int n) {
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for (int i = 0; i < n; i++) {
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function();
|
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}
|
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}
|
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/* 递归 O(n) */
|
||||
/* 递归的空间复杂度为 O(n) */
|
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void recur(int n) {
|
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if (n == 1) return;
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return recur(n - 1);
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|
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@ -711,13 +738,13 @@ comments: true
|
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// 执行某些操作
|
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return 0;
|
||||
}
|
||||
/* 循环 O(1) */
|
||||
/* 循环的空间复杂度为 O(1) */
|
||||
fn loop(n: i32) {
|
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for i in 0..n {
|
||||
function();
|
||||
}
|
||||
}
|
||||
/* 递归 O(n) */
|
||||
/* 递归的空间复杂度为 O(n) */
|
||||
fn recur(n: i32) {
|
||||
if n == 1 {
|
||||
return;
|
||||
|
|
@ -733,13 +760,13 @@ comments: true
|
|||
// 执行某些操作
|
||||
return 0;
|
||||
}
|
||||
/* 循环 O(1) */
|
||||
/* 循环的空间复杂度为 O(1) */
|
||||
void loop(int n) {
|
||||
for (int i = 0; i < n; i++) {
|
||||
func();
|
||||
}
|
||||
}
|
||||
/* 递归 O(n) */
|
||||
/* 递归的空间复杂度为 O(n) */
|
||||
void recur(int n) {
|
||||
if (n == 1) return;
|
||||
return recur(n - 1);
|
||||
|
|
@ -753,13 +780,13 @@ comments: true
|
|||
// 执行某些操作
|
||||
return 0
|
||||
}
|
||||
/* 循环 O(1) */
|
||||
/* 循环的空间复杂度为 O(1) */
|
||||
fun loop(n: Int) {
|
||||
for (i in 0..<n) {
|
||||
function()
|
||||
}
|
||||
}
|
||||
/* 递归 O(n) */
|
||||
/* 递归的空间复杂度为 O(n) */
|
||||
fun recur(n: Int) {
|
||||
if (n == 1) return
|
||||
return recur(n - 1)
|
||||
|
|
@ -769,7 +796,21 @@ comments: true
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title=""
|
||||
def function
|
||||
# 执行某些操作
|
||||
0
|
||||
end
|
||||
|
||||
### 循环的空间复杂度为 O(1) ###
|
||||
def loop(n)
|
||||
(0...n).each { function }
|
||||
end
|
||||
|
||||
### 递归的空间复杂度为 O(n) ###
|
||||
def recur(n)
|
||||
return if n == 1
|
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recur(n - 1)
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1134,9 +1175,24 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{function}
|
||||
### 函数 ###
|
||||
def function
|
||||
# 执行某些操作
|
||||
0
|
||||
end
|
||||
|
||||
[class]{}-[func]{constant}
|
||||
### 常数阶 ###
|
||||
def constant(n)
|
||||
# 常量、变量、对象占用 O(1) 空间
|
||||
a = 0
|
||||
nums = [0] * 10000
|
||||
node = ListNode.new
|
||||
|
||||
# 循环中的变量占用 O(1) 空间
|
||||
(0...n).each { c = 0 }
|
||||
# 循环中的函数占用 O(1) 空间
|
||||
(0...n).each { function }
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1438,7 +1494,17 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{linear}
|
||||
### 线性阶 ###
|
||||
def linear(n)
|
||||
# 长度为 n 的列表占用 O(n) 空间
|
||||
nums = Array.new(n, 0)
|
||||
|
||||
# 长度为 n 的哈希表占用 O(n) 空间
|
||||
hmap = {}
|
||||
for i in 0...n
|
||||
hmap[i] = i.to_s
|
||||
end
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1620,7 +1686,12 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{linear_recur}
|
||||
### 线性阶（递归实现）###
|
||||
def linear_recur(n)
|
||||
puts "递归 n = #{n}"
|
||||
return if n == 1
|
||||
linear_recur(n - 1)
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1860,7 +1931,11 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{quadratic}
|
||||
### 平方阶 ###
|
||||
def quadratic(n)
|
||||
# 二维列表占用 O(n^2) 空间
|
||||
Array.new(n) { Array.new(n, 0) }
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2055,7 +2130,14 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{quadratic_recur}
|
||||
### 平方阶（递归实现）###
|
||||
def quadratic_recur(n)
|
||||
return 0 unless n > 0
|
||||
|
||||
# 数组 nums 长度为 n, n-1, ..., 2, 1
|
||||
nums = Array.new(n, 0)
|
||||
quadratic_recur(n - 1)
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2253,7 +2335,15 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{build_tree}
|
||||
### 指数阶（建立满二叉树）###
|
||||
def build_tree(n)
|
||||
return if n == 0
|
||||
|
||||
TreeNode.new.tap do |root|
|
||||
root.left = build_tree(n - 1)
|
||||
root.right = build_tree(n - 1)
|
||||
end
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
|
|||
|
|
@ -193,7 +193,16 @@ comments: true
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title=""
|
||||
|
||||
# 在某运行平台下
|
||||
def algorithm(n)
|
||||
a = 2 # 1 ns
|
||||
a = a + 1 # 1 ns
|
||||
a = a * 2 # 10 ns
|
||||
# 循环 n 次
|
||||
(n...0).each do # 1 ns
|
||||
puts 0 # 5 ns
|
||||
end
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -478,7 +487,20 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title=""
|
||||
# 算法 A 的时间复杂度：常数阶
|
||||
def algorithm_A(n)
|
||||
puts 0
|
||||
end
|
||||
|
||||
# 算法 B 的时间复杂度：线性阶
|
||||
def algorithm_B(n)
|
||||
(0...n).each { puts 0 }
|
||||
end
|
||||
|
||||
# 算法 C 的时间复杂度：常数阶
|
||||
def algorithm_C(n)
|
||||
(0...1_000_000).each { puts 0 }
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -694,7 +716,15 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title=""
|
||||
|
||||
def algorithm(n)
|
||||
a = 1 # +1
|
||||
a = a + 1 # +1
|
||||
a = a * 2 # +1
|
||||
# 循环 n 次
|
||||
(0...n).each do # +1
|
||||
puts 0 # +1
|
||||
end
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -978,7 +1008,16 @@ $T(n)$ 是一次函数，说明其运行时间的增长趋势是线性的，因
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title=""
|
||||
|
||||
def algorithm(n)
|
||||
a = 1 # +0（技巧 1）
|
||||
a = a + n # +0（技巧 1）
|
||||
# +n（技巧 2）
|
||||
(0...(5 * n + 1)).each do { puts 0 }
|
||||
# +n*n（技巧 3）
|
||||
(0...(2 * n)).each do
|
||||
(0...(n + 1)).each do { puts 0 }
|
||||
end
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1216,7 +1255,15 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{constant}
|
||||
### 常数阶 ###
|
||||
def constant(n)
|
||||
count = 0
|
||||
size = 100000
|
||||
|
||||
(0...size).each { count += 1 }
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1394,7 +1441,12 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{linear}
|
||||
### 线性阶 ###
|
||||
def linear(n)
|
||||
count = 0
|
||||
(0...n).each { count += 1 }
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1587,7 +1639,17 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{array_traversal}
|
||||
### 线性阶（遍历数组）###
|
||||
def array_traversal(nums)
|
||||
count = 0
|
||||
|
||||
# 循环次数与数组长度成正比
|
||||
for num in nums
|
||||
count += 1
|
||||
end
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1807,7 +1869,19 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{quadratic}
|
||||
### 平方阶 ###
|
||||
def quadratic(n)
|
||||
count = 0
|
||||
|
||||
# 循环次数与数据大小 n 成平方关系
|
||||
for i in 0...n
|
||||
for j in 0...n
|
||||
count += 1
|
||||
end
|
||||
end
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2113,7 +2187,26 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{bubble_sort}
|
||||
### 平方阶（冒泡排序）###
|
||||
def bubble_sort(nums)
|
||||
count = 0 # 计数器
|
||||
|
||||
# 外循环：未排序区间为 [0, i]
|
||||
for i in (nums.length - 1).downto(0)
|
||||
# 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
|
||||
for j in 0...i
|
||||
if nums[j] > nums[j + 1]
|
||||
# 交换 nums[j] 与 nums[j + 1]
|
||||
tmp = nums[j]
|
||||
nums[j] = nums[j + 1]
|
||||
nums[j + 1] = tmp
|
||||
count += 3 # 元素交换包含 3 个单元操作
|
||||
end
|
||||
end
|
||||
end
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2375,7 +2468,19 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{exponential}
|
||||
### 指数阶（循环实现）###
|
||||
def exponential(n)
|
||||
count, base = 0, 1
|
||||
|
||||
# 细胞每轮一分为二，形成数列 1, 2, 4, 8, ..., 2^(n-1)
|
||||
(0...n).each do
|
||||
(0...base).each { count += 1 }
|
||||
base *= 2
|
||||
end
|
||||
|
||||
# count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2544,7 +2649,11 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{exp_recur}
|
||||
### 指数阶（递归实现）###
|
||||
def exp_recur(n)
|
||||
return 1 if n == 1
|
||||
exp_recur(n - 1) + exp_recur(n - 1) + 1
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2741,7 +2850,17 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{logarithmic}
|
||||
### 对数阶（循环实现）###
|
||||
def logarithmic(n)
|
||||
count = 0
|
||||
|
||||
while n > 1
|
||||
n /= 2
|
||||
count += 1
|
||||
end
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2904,7 +3023,11 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{log_recur}
|
||||
### 对数阶（递归实现）###
|
||||
def log_recur(n)
|
||||
return 0 unless n > 1
|
||||
log_recur(n / 2) + 1
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -3118,7 +3241,15 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{linear_log_recur}
|
||||
### 线性对数阶 ###
|
||||
def linear_log_recur(n)
|
||||
return 1 unless n > 1
|
||||
|
||||
count = linear_log_recur(n / 2) + linear_log_recur(n / 2)
|
||||
(0...n).each { count += 1 }
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -3350,7 +3481,16 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{factorial_recur}
|
||||
### 阶乘阶（递归实现）###
|
||||
def factorial_recur(n)
|
||||
return 1 if n == 0
|
||||
|
||||
count = 0
|
||||
# 从 1 个分裂出 n 个
|
||||
(0...n).each { count += factorial_recur(n - 1) }
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -3745,9 +3885,24 @@ $$
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="worst_best_time_complexity.rb"
|
||||
[class]{}-[func]{random_numbers}
|
||||
### 生成一个数组，元素为: 1, 2, ..., n ，顺序被打乱 ###
|
||||
def random_numbers(n)
|
||||
# 生成数组 nums =: 1, 2, 3, ..., n
|
||||
nums = Array.new(n) { |i| i + 1 }
|
||||
# 随机打乱数组元素
|
||||
nums.shuffle!
|
||||
end
|
||||
|
||||
[class]{}-[func]{find_one}
|
||||
### 查找数组 nums 中数字 1 所在索引 ###
|
||||
def find_one(nums)
|
||||
for i in 0...nums.length
|
||||
# 当元素 1 在数组头部时，达到最佳时间复杂度 O(1)
|
||||
# 当元素 1 在数组尾部时，达到最差时间复杂度 O(n)
|
||||
return i if nums[i] == 1
|
||||
end
|
||||
|
||||
-1
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
|
|||
|
|
@ -299,7 +299,7 @@ Accessing elements in an array is highly efficient, allowing us to randomly acce
|
|||
### 随机访问元素 ###
|
||||
def random_access(nums)
|
||||
# 在区间 [0, nums.length) 中随机抽取一个数字
|
||||
random_index = Random.rand 0...(nums.length - 1)
|
||||
random_index = Random.rand(0...nums.length)
|
||||
|
||||
# 获取并返回随机元素
|
||||
nums[random_index]
|
||||
|
|
|
|||
|
|
@ -2154,7 +2154,7 @@ To enhance our understanding of how lists work, we will attempt to implement a s
|
|||
@capacity = 10
|
||||
@size = 0
|
||||
@extend_ratio = 2
|
||||
@arr = Array.new capacity
|
||||
@arr = Array.new(capacity)
|
||||
end
|
||||
|
||||
### 访问元素 ###
|
||||
|
|
@ -2226,9 +2226,9 @@ To enhance our understanding of how lists work, we will attempt to implement a s
|
|||
def to_array
|
||||
sz = size
|
||||
# 仅转换有效长度范围内的列表元素
|
||||
arr = Array.new sz
|
||||
arr = Array.new(sz)
|
||||
for i in 0...sz
|
||||
arr[i] = get i
|
||||
arr[i] = get(i)
|
||||
end
|
||||
arr
|
||||
end
|
||||
|
|
|
|||
|
|
@ -185,7 +185,17 @@ The following function uses a `for` loop to perform a summation of $1 + 2 + \dot
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="iteration.rb"
|
||||
[class]{}-[func]{for_loop}
|
||||
### for 循环 ###
|
||||
def for_loop(n)
|
||||
res = 0
|
||||
|
||||
# 循环求和 1, 2, ..., n-1, n
|
||||
for i in 1..n
|
||||
res += i
|
||||
end
|
||||
|
||||
res
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -417,7 +427,19 @@ Below we use a `while` loop to implement the sum $1 + 2 + \dots + n$.
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="iteration.rb"
|
||||
[class]{}-[func]{while_loop}
|
||||
### while 循环 ###
|
||||
def while_loop(n)
|
||||
res = 0
|
||||
i = 1 # 初始化条件变量
|
||||
|
||||
# 循环求和 1, 2, ..., n-1, n
|
||||
while i <= n
|
||||
res += i
|
||||
i += 1 # 更新条件变量
|
||||
end
|
||||
|
||||
res
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -664,7 +686,21 @@ For example, in the following code, the condition variable $i$ is updated twice
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="iteration.rb"
|
||||
[class]{}-[func]{while_loop_ii}
|
||||
### while 循环（两次更新）###
|
||||
def while_loop_ii(n)
|
||||
res = 0
|
||||
i = 1 # 初始化条件变量
|
||||
|
||||
# 循环求和 1, 4, 10, ...
|
||||
while i <= n
|
||||
res += i
|
||||
# 更新条件变量
|
||||
i += 1
|
||||
i *= 2
|
||||
end
|
||||
|
||||
res
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -904,7 +940,20 @@ We can nest one loop structure within another. Below is an example using `for` l
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="iteration.rb"
|
||||
[class]{}-[func]{nested_for_loop}
|
||||
### 双层 for 循环 ###
|
||||
def nested_for_loop(n)
|
||||
res = ""
|
||||
|
||||
# 循环 i = 1, 2, ..., n-1, n
|
||||
for i in 1..n
|
||||
# 循环 j = 1, 2, ..., n-1, n
|
||||
for j in 1..n
|
||||
res += "(#{i}, #{j}), "
|
||||
end
|
||||
end
|
||||
|
||||
res
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1139,7 +1188,15 @@ Observe the following code, where simply calling the function `recur(n)` can com
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="recursion.rb"
|
||||
[class]{}-[func]{recur}
|
||||
### 递归 ###
|
||||
def recur(n)
|
||||
# 终止条件
|
||||
return 1 if n == 1
|
||||
# 递：递归调用
|
||||
res = recur(n - 1)
|
||||
# 归：返回结果
|
||||
n + res
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1362,7 +1419,13 @@ For example, in calculating $1 + 2 + \dots + n$, we can make the result variable
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="recursion.rb"
|
||||
[class]{}-[func]{tail_recur}
|
||||
### 尾递归 ###
|
||||
def tail_recur(n, res)
|
||||
# 终止条件
|
||||
return res if n == 0
|
||||
# 尾递归调用
|
||||
tail_recur(n - 1, res + n)
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1594,7 +1657,15 @@ Using the recursive relation, and considering the first two numbers as terminati
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="recursion.rb"
|
||||
[class]{}-[func]{fib}
|
||||
### 斐波那契数列：递归 ###
|
||||
def fib(n)
|
||||
# 终止条件 f(1) = 0, f(2) = 1
|
||||
return n - 1 if n == 1 || n == 2
|
||||
# 递归调用 f(n) = f(n-1) + f(n-2)
|
||||
res = fib(n - 1) + fib(n - 2)
|
||||
# 返回结果 f(n)
|
||||
res
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1936,7 +2007,25 @@ Therefore, **we can use an explicit stack to simulate the behavior of the call s
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="recursion.rb"
|
||||
[class]{}-[func]{for_loop_recur}
|
||||
### 使用迭代模拟递归 ###
|
||||
def for_loop_recur(n)
|
||||
# 使用一个显式的栈来模拟系统调用栈
|
||||
stack = []
|
||||
res = 0
|
||||
|
||||
# 递：递归调用
|
||||
for i in n.downto(0)
|
||||
# 通过“入栈操作”模拟“递”
|
||||
stack << i
|
||||
end
|
||||
# 归：返回结果
|
||||
while !stack.empty?
|
||||
res += stack.pop
|
||||
end
|
||||
|
||||
# res = 1+2+3+...+n
|
||||
res
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
|
|||
|
|
@ -1080,9 +1080,24 @@ Note that memory occupied by initializing variables or calling functions in a lo
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{function}
|
||||
### 函数 ###
|
||||
def function
|
||||
# 执行某些操作
|
||||
0
|
||||
end
|
||||
|
||||
[class]{}-[func]{constant}
|
||||
### 常数阶 ###
|
||||
def constant(n)
|
||||
# 常量、变量、对象占用 O(1) 空间
|
||||
a = 0
|
||||
nums = [0] * 10000
|
||||
node = ListNode.new
|
||||
|
||||
# 循环中的变量占用 O(1) 空间
|
||||
(0...n).each { c = 0 }
|
||||
# 循环中的函数占用 O(1) 空间
|
||||
(0...n).each { function }
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1384,7 +1399,17 @@ Linear order is common in arrays, linked lists, stacks, queues, etc., where the
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{linear}
|
||||
### 线性阶 ###
|
||||
def linear(n)
|
||||
# 长度为 n 的列表占用 O(n) 空间
|
||||
nums = Array.new(n, 0)
|
||||
|
||||
# 长度为 n 的哈希表占用 O(n) 空间
|
||||
hmap = {}
|
||||
for i in 0...n
|
||||
hmap[i] = i.to_s
|
||||
end
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1566,7 +1591,12 @@ As shown below, this function's recursive depth is $n$, meaning there are $n$ in
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{linear_recur}
|
||||
### 线性阶（递归实现）###
|
||||
def linear_recur(n)
|
||||
puts "递归 n = #{n}"
|
||||
return if n == 1
|
||||
linear_recur(n - 1)
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1806,7 +1836,11 @@ Quadratic order is common in matrices and graphs, where the number of elements i
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{quadratic}
|
||||
### 平方阶 ###
|
||||
def quadratic(n)
|
||||
# 二维列表占用 O(n^2) 空间
|
||||
Array.new(n) { Array.new(n, 0) }
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2001,7 +2035,14 @@ As shown below, the recursive depth of this function is $n$, and in each recursi
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{quadratic_recur}
|
||||
### 平方阶（递归实现）###
|
||||
def quadratic_recur(n)
|
||||
return 0 unless n > 0
|
||||
|
||||
# 数组 nums 长度为 n, n-1, ..., 2, 1
|
||||
nums = Array.new(n, 0)
|
||||
quadratic_recur(n - 1)
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2199,7 +2240,15 @@ Exponential order is common in binary trees. Observe the below image, a "full bi
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="space_complexity.rb"
|
||||
[class]{}-[func]{build_tree}
|
||||
### 指数阶（建立满二叉树）###
|
||||
def build_tree(n)
|
||||
return if n == 0
|
||||
|
||||
TreeNode.new.tap do |root|
|
||||
root.left = build_tree(n - 1)
|
||||
root.right = build_tree(n - 1)
|
||||
end
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
|
|||
|
|
@ -1143,7 +1143,15 @@ Constant order means the number of operations is independent of the input data s
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{constant}
|
||||
### 常数阶 ###
|
||||
def constant(n)
|
||||
count = 0
|
||||
size = 100000
|
||||
|
||||
(0...size).each { count += 1 }
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1321,7 +1329,12 @@ Linear order indicates the number of operations grows linearly with the input da
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{linear}
|
||||
### 线性阶 ###
|
||||
def linear(n)
|
||||
count = 0
|
||||
(0...n).each { count += 1 }
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1514,7 +1527,17 @@ Operations like array traversal and linked list traversal have a time complexity
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{array_traversal}
|
||||
### 线性阶（遍历数组）###
|
||||
def array_traversal(nums)
|
||||
count = 0
|
||||
|
||||
# 循环次数与数组长度成正比
|
||||
for num in nums
|
||||
count += 1
|
||||
end
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -1734,7 +1757,19 @@ Quadratic order means the number of operations grows quadratically with the inpu
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{quadratic}
|
||||
### 平方阶 ###
|
||||
def quadratic(n)
|
||||
count = 0
|
||||
|
||||
# 循环次数与数据大小 n 成平方关系
|
||||
for i in 0...n
|
||||
for j in 0...n
|
||||
count += 1
|
||||
end
|
||||
end
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2040,7 +2075,26 @@ For instance, in bubble sort, the outer loop runs $n - 1$ times, and the inner l
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{bubble_sort}
|
||||
### 平方阶（冒泡排序）###
|
||||
def bubble_sort(nums)
|
||||
count = 0 # 计数器
|
||||
|
||||
# 外循环：未排序区间为 [0, i]
|
||||
for i in (nums.length - 1).downto(0)
|
||||
# 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
|
||||
for j in 0...i
|
||||
if nums[j] > nums[j + 1]
|
||||
# 交换 nums[j] 与 nums[j + 1]
|
||||
tmp = nums[j]
|
||||
nums[j] = nums[j + 1]
|
||||
nums[j + 1] = tmp
|
||||
count += 3 # 元素交换包含 3 个单元操作
|
||||
end
|
||||
end
|
||||
end
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2302,7 +2356,19 @@ The following image and code simulate the cell division process, with a time com
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{exponential}
|
||||
### 指数阶（循环实现）###
|
||||
def exponential(n)
|
||||
count, base = 0, 1
|
||||
|
||||
# 细胞每轮一分为二，形成数列 1, 2, 4, 8, ..., 2^(n-1)
|
||||
(0...n).each do
|
||||
(0...base).each { count += 1 }
|
||||
base *= 2
|
||||
end
|
||||
|
||||
# count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2471,7 +2537,11 @@ In practice, exponential order often appears in recursive functions. For example
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{exp_recur}
|
||||
### 指数阶（递归实现）###
|
||||
def exp_recur(n)
|
||||
return 1 if n == 1
|
||||
exp_recur(n - 1) + exp_recur(n - 1) + 1
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2668,7 +2738,17 @@ The following image and code simulate the "halving each round" process, with a t
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{logarithmic}
|
||||
### 对数阶（循环实现）###
|
||||
def logarithmic(n)
|
||||
count = 0
|
||||
|
||||
while n > 1
|
||||
n /= 2
|
||||
count += 1
|
||||
end
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -2831,7 +2911,11 @@ Like exponential order, logarithmic order also frequently appears in recursive f
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{log_recur}
|
||||
### 对数阶（递归实现）###
|
||||
def log_recur(n)
|
||||
return 0 unless n > 1
|
||||
log_recur(n / 2) + 1
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -3045,7 +3129,15 @@ Linear-logarithmic order often appears in nested loops, with the complexities of
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{linear_log_recur}
|
||||
### 线性对数阶 ###
|
||||
def linear_log_recur(n)
|
||||
return 1 unless n > 1
|
||||
|
||||
count = linear_log_recur(n / 2) + linear_log_recur(n / 2)
|
||||
(0...n).each { count += 1 }
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -3277,7 +3369,16 @@ Factorials are typically implemented using recursion. As shown in the image and
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="time_complexity.rb"
|
||||
[class]{}-[func]{factorial_recur}
|
||||
### 阶乘阶（递归实现）###
|
||||
def factorial_recur(n)
|
||||
return 1 if n == 0
|
||||
|
||||
count = 0
|
||||
# 从 1 个分裂出 n 个
|
||||
(0...n).each { count += factorial_recur(n - 1) }
|
||||
|
||||
count
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
@ -3672,9 +3773,24 @@ The "worst-case time complexity" corresponds to the asymptotic upper bound, deno
|
|||
=== "Ruby"
|
||||
|
||||
```ruby title="worst_best_time_complexity.rb"
|
||||
[class]{}-[func]{random_numbers}
|
||||
### 生成一个数组，元素为: 1, 2, ..., n ，顺序被打乱 ###
|
||||
def random_numbers(n)
|
||||
# 生成数组 nums =: 1, 2, 3, ..., n
|
||||
nums = Array.new(n) { |i| i + 1 }
|
||||
# 随机打乱数组元素
|
||||
nums.shuffle!
|
||||
end
|
||||
|
||||
[class]{}-[func]{find_one}
|
||||
### 查找数组 nums 中数字 1 所在索引 ###
|
||||
def find_one(nums)
|
||||
for i in 0...nums.length
|
||||
# 当元素 1 在数组头部时，达到最佳时间复杂度 O(1)
|
||||
# 当元素 1 在数组尾部时，达到最差时间复杂度 O(n)
|
||||
return i if nums[i] == 1
|
||||
end
|
||||
|
||||
-1
|
||||
end
|
||||
```
|
||||
|
||||
=== "Zig"
|
||||
|
|
|
|||
Loading…
Reference in a new issue