hello-algo/codes/kotlin/chapter_backtracking/subset_sum_ii.kt
curtishd 306dc019ef
Add Kotlin code for computational complexity (#1090)
* feat(kotlin):new kotlin support files

* fix(kotlin):

    reviewed the formatting, comments and so on.

* fix(kotlin): fix the indentation and format

* feat(kotlin): Add kotlin code for the backtraking chapter.

* fix(kotlin): fix incorrect output of preorder_traversal_iii_template.kt file

* fix(kotlin): simplify kotlin codes

* fix(kotlin): modify n_queens.kt for consistency.

* feat(kotlin): add kotlin code for computational complexity.

* fix(kotlin): remove iteration folder.

* fix(kotlin): remove n_queens.kt file out of folder.

* fix(kotlin): remove some folders.

* style(kotlin): modified two chapters.
2024-02-27 17:04:57 +08:00

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2 KiB
Kotlin

/**
* File: subset_sum_ii.kt
* Created Time: 2024-01-25
* Author: curtishd (1023632660@qq.com)
*/
package chapter_backtracking.subset_sum_ii
import java.util.*
/* 回溯算法:子集和 II */
fun backtrack(
state: MutableList<Int>,
target: Int,
choices: IntArray,
start: Int,
res: MutableList<List<Int>?>
) {
// 子集和等于 target 时,记录解
if (target == 0) {
res.add(ArrayList(state))
return
}
// 遍历所有选择
// 剪枝二:从 start 开始遍历,避免生成重复子集
// 剪枝三:从 start 开始遍历,避免重复选择同一元素
for (i in start..<choices.size) {
// 剪枝一:若子集和超过 target ,则直接结束循环
// 这是因为数组已排序,后边元素更大,子集和一定超过 target
if (target - choices[i] < 0) {
break
}
// 剪枝四:如果该元素与左边元素相等,说明该搜索分支重复,直接跳过
if (i > start && choices[i] == choices[i - 1]) {
continue
}
// 尝试:做出选择,更新 target, start
state.add(choices[i])
// 进行下一轮选择
backtrack(state, target - choices[i], choices, i + 1, res)
// 回退:撤销选择,恢复到之前的状态
state.removeAt(state.size - 1)
}
}
/* 求解子集和 II */
fun subsetSumII(nums: IntArray, target: Int): List<List<Int>?> {
val state: MutableList<Int> = ArrayList() // 状态(子集)
Arrays.sort(nums) // 对 nums 进行排序
val start = 0 // 遍历起始点
val res: MutableList<List<Int>?> = ArrayList() // 结果列表(子集列表)
backtrack(state, target, nums, start, res)
return res
}
/* Driver Code */
fun main() {
val nums = intArrayOf(4, 4, 5)
val target = 9
val res = subsetSumII(nums, target)
println("输入数组 nums = ${nums.contentToString()}, target = $target")
println("所有和等于 $target 的子集 res = $res")
}