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* Modify method name to PascalCase(array and linked list) * Modify method name to PascalCase(backtracking) * Modify method name to PascalCase(computational complexity) * Modify method name to PascalCase(divide and conquer) * Modify method name to PascalCase(dynamic programming) * Modify method name to PascalCase(graph) * Modify method name to PascalCase(greedy) * Modify method name to PascalCase(hashing) * Modify method name to PascalCase(heap) * Modify method name to PascalCase(searching) * Modify method name to PascalCase(sorting) * Modify method name to PascalCase(stack and queue) * Modify method name to PascalCase(tree) * local check
55 lines
1.8 KiB
C#
55 lines
1.8 KiB
C#
/**
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* File: permutations_ii.cs
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* Created Time: 2023-04-24
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* Author: hpstory (hpstory1024@163.com)
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*/
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namespace hello_algo.chapter_backtracking;
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public class permutations_ii {
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/* 回溯算法:全排列 II */
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static void Backtrack(List<int> state, int[] choices, bool[] selected, List<List<int>> res) {
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// 当状态长度等于元素数量时,记录解
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if (state.Count == choices.Length) {
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res.Add(new List<int>(state));
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return;
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}
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// 遍历所有选择
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ISet<int> duplicated = new HashSet<int>();
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for (int i = 0; i < choices.Length; i++) {
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int choice = choices[i];
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// 剪枝:不允许重复选择元素 且 不允许重复选择相等元素
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if (!selected[i] && !duplicated.Contains(choice)) {
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// 尝试:做出选择,更新状态
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duplicated.Add(choice); // 记录选择过的元素值
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selected[i] = true;
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state.Add(choice);
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// 进行下一轮选择
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Backtrack(state, choices, selected, res);
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// 回退:撤销选择,恢复到之前的状态
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selected[i] = false;
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state.RemoveAt(state.Count - 1);
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}
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}
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}
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/* 全排列 II */
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static List<List<int>> PermutationsII(int[] nums) {
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List<List<int>> res = new();
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Backtrack(new List<int>(), nums, new bool[nums.Length], res);
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return res;
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}
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[Test]
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public void Test() {
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int[] nums = { 1, 2, 2 };
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List<List<int>> res = PermutationsII(nums);
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Console.WriteLine("输入数组 nums = " + string.Join(", ", nums));
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Console.WriteLine("所有排列 res = ");
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foreach (List<int> permutation in res) {
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PrintUtil.PrintList(permutation);
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}
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}
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}
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