hello-algo/codes/rust/chapter_divide_and_conquer/build_tree.rs
rongyi 7b1094318b
cargo fmt rust code (#1131)
* cargo fmt code

* Add empty line to seperate unrelated comments

* Fix review

* Update bubble_sort.rs

* Update merge_sort.rs

---------

Co-authored-by: Yudong Jin <krahets@163.com>
2024-03-16 02:13:41 +08:00

57 lines
1.6 KiB
Rust

/*
* File: build_tree.rs
* Created Time: 2023-07-15
* Author: codingonion (coderonion@gmail.com)
*/
use std::collections::HashMap;
use std::{cell::RefCell, rc::Rc};
include!("../include/include.rs");
use tree_node::TreeNode;
/* 构建二叉树:分治 */
fn dfs(
preorder: &[i32],
inorder_map: &HashMap<i32, i32>,
i: i32,
l: i32,
r: i32,
) -> Option<Rc<RefCell<TreeNode>>> {
// 子树区间为空时终止
if r - l < 0 {
return None;
}
// 初始化根节点
let root = TreeNode::new(preorder[i as usize]);
// 查询 m ,从而划分左右子树
let m = inorder_map.get(&preorder[i as usize]).unwrap();
// 子问题:构建左子树
root.borrow_mut().left = dfs(preorder, inorder_map, i + 1, l, m - 1);
// 子问题:构建右子树
root.borrow_mut().right = dfs(preorder, inorder_map, i + 1 + m - l, m + 1, r);
// 返回根节点
Some(root)
}
/* 构建二叉树 */
fn build_tree(preorder: &[i32], inorder: &[i32]) -> Option<Rc<RefCell<TreeNode>>> {
// 初始化哈希表,存储 inorder 元素到索引的映射
let mut inorder_map: HashMap<i32, i32> = HashMap::new();
for i in 0..inorder.len() {
inorder_map.insert(inorder[i], i as i32);
}
let root = dfs(preorder, &inorder_map, 0, 0, inorder.len() as i32 - 1);
root
}
/* Driver Code */
fn main() {
let preorder = [3, 9, 2, 1, 7];
let inorder = [9, 3, 1, 2, 7];
println!("中序遍历 = {:?}", preorder);
println!("前序遍历 = {:?}", inorder);
let root = build_tree(&preorder, &inorder);
println!("构建的二叉树为:");
print_util::print_tree(root.as_ref().unwrap());
}