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7b1094318b
* cargo fmt code * Add empty line to seperate unrelated comments * Fix review * Update bubble_sort.rs * Update merge_sort.rs --------- Co-authored-by: Yudong Jin <krahets@163.com>
117 lines
2.5 KiB
Rust
117 lines
2.5 KiB
Rust
/*
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* File: space_complexity.rs
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* Created Time: 2023-03-11
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* Author: codingonion (coderonion@gmail.com)
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*/
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include!("../include/include.rs");
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use list_node::ListNode;
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use std::cell::RefCell;
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use std::collections::HashMap;
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use std::rc::Rc;
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use tree_node::TreeNode;
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/* 函数 */
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fn function() -> i32 {
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// 执行某些操作
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return 0;
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}
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/* 常数阶 */
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#[allow(unused)]
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fn constant(n: i32) {
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// 常量、变量、对象占用 O(1) 空间
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const A: i32 = 0;
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let b = 0;
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let nums = vec![0; 10000];
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let node = ListNode::new(0);
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// 循环中的变量占用 O(1) 空间
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for i in 0..n {
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let c = 0;
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}
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// 循环中的函数占用 O(1) 空间
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for i in 0..n {
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function();
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}
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}
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/* 线性阶 */
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#[allow(unused)]
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fn linear(n: i32) {
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// 长度为 n 的数组占用 O(n) 空间
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let mut nums = vec![0; n as usize];
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// 长度为 n 的列表占用 O(n) 空间
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let mut nodes = Vec::new();
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for i in 0..n {
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nodes.push(ListNode::new(i))
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}
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// 长度为 n 的哈希表占用 O(n) 空间
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let mut map = HashMap::new();
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for i in 0..n {
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map.insert(i, i.to_string());
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}
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}
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/* 线性阶(递归实现) */
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fn linear_recur(n: i32) {
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println!("递归 n = {}", n);
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if n == 1 {
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return;
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};
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linear_recur(n - 1);
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}
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/* 平方阶 */
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#[allow(unused)]
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fn quadratic(n: i32) {
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// 矩阵占用 O(n^2) 空间
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let num_matrix = vec![vec![0; n as usize]; n as usize];
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// 二维列表占用 O(n^2) 空间
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let mut num_list = Vec::new();
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for i in 0..n {
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let mut tmp = Vec::new();
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for j in 0..n {
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tmp.push(0);
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}
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num_list.push(tmp);
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}
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}
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/* 平方阶(递归实现) */
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fn quadratic_recur(n: i32) -> i32 {
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if n <= 0 {
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return 0;
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};
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// 数组 nums 长度为 n, n-1, ..., 2, 1
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let nums = vec![0; n as usize];
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println!("递归 n = {} 中的 nums 长度 = {}", n, nums.len());
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return quadratic_recur(n - 1);
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}
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/* 指数阶(建立满二叉树) */
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fn build_tree(n: i32) -> Option<Rc<RefCell<TreeNode>>> {
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if n == 0 {
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return None;
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};
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let root = TreeNode::new(0);
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root.borrow_mut().left = build_tree(n - 1);
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root.borrow_mut().right = build_tree(n - 1);
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return Some(root);
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}
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/* Driver Code */
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fn main() {
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let n = 5;
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// 常数阶
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constant(n);
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// 线性阶
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linear(n);
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linear_recur(n);
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// 平方阶
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quadratic(n);
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quadratic_recur(n);
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// 指数阶
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let root = build_tree(n);
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print_util::print_tree(&root.unwrap());
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}
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