hello-algo/codes/go/chapter_backtracking/n_queens.go
Yudong Jin f6976978dd
Prepare 1.0.0 release (#1044)
* Update the book with the thrid revised edition

* Fix a typo

* Update the contributors' information

* Update the mindmap

* Update the version number
2024-01-14 03:16:20 +08:00

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// File: n_queens.go
// Created Time: 2023-05-09
// Author: Reanon (793584285@qq.com)
package chapter_backtracking
/* 回溯算法n 皇后 */
func backtrack(row, n int, state *[][]string, res *[][][]string, cols, diags1, diags2 *[]bool) {
// 当放置完所有行时,记录解
if row == n {
newState := make([][]string, len(*state))
for i, _ := range newState {
newState[i] = make([]string, len((*state)[0]))
copy(newState[i], (*state)[i])
}
*res = append(*res, newState)
}
// 遍历所有列
for col := 0; col < n; col++ {
// 计算该格子对应的主对角线和次对角线
diag1 := row - col + n - 1
diag2 := row + col
// 剪枝:不允许该格子所在列、主对角线、次对角线上存在皇后
if !(*cols)[col] && !(*diags1)[diag1] && !(*diags2)[diag2] {
// 尝试:将皇后放置在该格子
(*state)[row][col] = "Q"
(*cols)[col], (*diags1)[diag1], (*diags2)[diag2] = true, true, true
// 放置下一行
backtrack(row+1, n, state, res, cols, diags1, diags2)
// 回退:将该格子恢复为空位
(*state)[row][col] = "#"
(*cols)[col], (*diags1)[diag1], (*diags2)[diag2] = false, false, false
}
}
}
/* 求解 n 皇后 */
func nQueens(n int) [][][]string {
// 初始化 n*n 大小的棋盘,其中 'Q' 代表皇后,'#' 代表空位
state := make([][]string, n)
for i := 0; i < n; i++ {
row := make([]string, n)
for i := 0; i < n; i++ {
row[i] = "#"
}
state[i] = row
}
// 记录列是否有皇后
cols := make([]bool, n)
diags1 := make([]bool, 2*n-1)
diags2 := make([]bool, 2*n-1)
res := make([][][]string, 0)
backtrack(0, n, &state, &res, &cols, &diags1, &diags2)
return res
}