hello-algo/codes/python/chapter_dynamic_programming/coin_change_ii.py
2023-11-03 22:48:43 +08:00

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"""
File: coin_change_ii.py
Created Time: 2023-07-10
Author: Krahets (krahets@163.com)
"""
def coin_change_ii_dp(coins: list[int], amt: int) -> int:
"""零钱兑换 II动态规划"""
n = len(coins)
# 初始化 dp 表
dp = [[0] * (amt + 1) for _ in range(n + 1)]
# 初始化首列
for i in range(n + 1):
dp[i][0] = 1
# 状态转移
for i in range(1, n + 1):
for a in range(1, amt + 1):
if coins[i - 1] > a:
# 若超过目标金额,则不选硬币 i
dp[i][a] = dp[i - 1][a]
else:
# 不选和选硬币 i 这两种方案之和
dp[i][a] = dp[i - 1][a] + dp[i][a - coins[i - 1]]
return dp[n][amt]
def coin_change_ii_dp_comp(coins: list[int], amt: int) -> int:
"""零钱兑换 II空间优化后的动态规划"""
n = len(coins)
# 初始化 dp 表
dp = [0] * (amt + 1)
dp[0] = 1
# 状态转移
for i in range(1, n + 1):
# 正序遍历
for a in range(1, amt + 1):
if coins[i - 1] > a:
# 若超过目标金额,则不选硬币 i
dp[a] = dp[a]
else:
# 不选和选硬币 i 这两种方案之和
dp[a] = dp[a] + dp[a - coins[i - 1]]
return dp[amt]
"""Driver Code"""
if __name__ == "__main__":
coins = [1, 2, 5]
amt = 5
n = len(coins)
# 动态规划
res = coin_change_ii_dp(coins, amt)
print(f"凑出目标金额的硬币组合数量为 {res}")
# 空间优化后的动态规划
res = coin_change_ii_dp_comp(coins, amt)
print(f"凑出目标金额的硬币组合数量为 {res}")