hello-algo/codes/java/chapter_tree/array_binary_tree.java
Yudong Jin ddd375af20
feat: Add visualizing code blocks based on the pythontutor (#1029)
* Update copyright

* Update the Python code

* Fix the code comments in ArrayBinaryTree

* Fix the code comments in ArrayBinaryTree

* Roll back time_comlexity.py

* Add the visualizing code(pythontutor) blocks to the chapter complexity, data structure, array and linked list, stack and queue, hash table, and backtracking

* Fix the code comments
2024-01-07 04:04:01 +08:00

136 lines
3.9 KiB
Java
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/**
* File: array_binary_tree.java
* Created Time: 2023-07-19
* Author: Krahets (krahets@163.com)
*/
package chapter_tree;
import utils.*;
import java.util.*;
/* 数组表示下的二叉树类 */
class ArrayBinaryTree {
private List<Integer> tree;
/* 构造方法 */
public ArrayBinaryTree(List<Integer> arr) {
tree = new ArrayList<>(arr);
}
/* 列表容量 */
public int size() {
return tree.size();
}
/* 获取索引为 i 节点的值 */
public Integer val(int i) {
// 若索引越界,则返回 null ,代表空位
if (i < 0 || i >= size())
return null;
return tree.get(i);
}
/* 获取索引为 i 节点的左子节点的索引 */
public Integer left(int i) {
return 2 * i + 1;
}
/* 获取索引为 i 节点的右子节点的索引 */
public Integer right(int i) {
return 2 * i + 2;
}
/* 获取索引为 i 节点的父节点的索引 */
public Integer parent(int i) {
return (i - 1) / 2;
}
/* 层序遍历 */
public List<Integer> levelOrder() {
List<Integer> res = new ArrayList<>();
// 直接遍历数组
for (int i = 0; i < size(); i++) {
if (val(i) != null)
res.add(val(i));
}
return res;
}
/* 深度优先遍历 */
private void dfs(Integer i, String order, List<Integer> res) {
// 若为空位,则返回
if (val(i) == null)
return;
// 前序遍历
if ("pre".equals(order))
res.add(val(i));
dfs(left(i), order, res);
// 中序遍历
if ("in".equals(order))
res.add(val(i));
dfs(right(i), order, res);
// 后序遍历
if ("post".equals(order))
res.add(val(i));
}
/* 前序遍历 */
public List<Integer> preOrder() {
List<Integer> res = new ArrayList<>();
dfs(0, "pre", res);
return res;
}
/* 中序遍历 */
public List<Integer> inOrder() {
List<Integer> res = new ArrayList<>();
dfs(0, "in", res);
return res;
}
/* 后序遍历 */
public List<Integer> postOrder() {
List<Integer> res = new ArrayList<>();
dfs(0, "post", res);
return res;
}
}
public class array_binary_tree {
public static void main(String[] args) {
// 初始化二叉树
// 这里借助了一个从数组直接生成二叉树的函数
List<Integer> arr = Arrays.asList(1, 2, 3, 4, null, 6, 7, 8, 9, null, null, 12, null, null, 15);
TreeNode root = TreeNode.listToTree(arr);
System.out.println("\n初始化二叉树\n");
System.out.println("二叉树的数组表示:");
System.out.println(arr);
System.out.println("二叉树的链表表示:");
PrintUtil.printTree(root);
// 数组表示下的二叉树类
ArrayBinaryTree abt = new ArrayBinaryTree(arr);
// 访问节点
int i = 1;
Integer l = abt.left(i);
Integer r = abt.right(i);
Integer p = abt.parent(i);
System.out.println("\n当前节点的索引为 " + i + " ,值为 " + abt.val(i));
System.out.println("其左子节点的索引为 " + l + " ,值为 " + (l == null ? "null" : abt.val(l)));
System.out.println("其右子节点的索引为 " + r + " ,值为 " + (r == null ? "null" : abt.val(r)));
System.out.println("其父节点的索引为 " + p + " ,值为 " + (p == null ? "null" : abt.val(p)));
// 遍历树
List<Integer> res = abt.levelOrder();
System.out.println("\n层序遍历为" + res);
res = abt.preOrder();
System.out.println("前序遍历为:" + res);
res = abt.inOrder();
System.out.println("中序遍历为:" + res);
res = abt.postOrder();
System.out.println("后序遍历为:" + res);
}
}