hello-algo/en/codes/python/chapter_dynamic_programming/edit_distance.py
Yudong Jin 1c0f350ad6
translation: Add Python and Java code for EN version (#1345)
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* Add Python and Java code for EN version
2024-05-06 05:21:51 +08:00

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Python

"""
File: edit_distancde.py
Created Time: 2023-07-04
Author: krahets (krahets@163.com)
"""
def edit_distance_dfs(s: str, t: str, i: int, j: int) -> int:
"""Edit distance: Brute force search"""
# If both s and t are empty, return 0
if i == 0 and j == 0:
return 0
# If s is empty, return the length of t
if i == 0:
return j
# If t is empty, return the length of s
if j == 0:
return i
# If the two characters are equal, skip these two characters
if s[i - 1] == t[j - 1]:
return edit_distance_dfs(s, t, i - 1, j - 1)
# The minimum number of edits = the minimum number of edits from three operations (insert, remove, replace) + 1
insert = edit_distance_dfs(s, t, i, j - 1)
delete = edit_distance_dfs(s, t, i - 1, j)
replace = edit_distance_dfs(s, t, i - 1, j - 1)
# Return the minimum number of edits
return min(insert, delete, replace) + 1
def edit_distance_dfs_mem(s: str, t: str, mem: list[list[int]], i: int, j: int) -> int:
"""Edit distance: Memoized search"""
# If both s and t are empty, return 0
if i == 0 and j == 0:
return 0
# If s is empty, return the length of t
if i == 0:
return j
# If t is empty, return the length of s
if j == 0:
return i
# If there is a record, return it
if mem[i][j] != -1:
return mem[i][j]
# If the two characters are equal, skip these two characters
if s[i - 1] == t[j - 1]:
return edit_distance_dfs_mem(s, t, mem, i - 1, j - 1)
# The minimum number of edits = the minimum number of edits from three operations (insert, remove, replace) + 1
insert = edit_distance_dfs_mem(s, t, mem, i, j - 1)
delete = edit_distance_dfs_mem(s, t, mem, i - 1, j)
replace = edit_distance_dfs_mem(s, t, mem, i - 1, j - 1)
# Record and return the minimum number of edits
mem[i][j] = min(insert, delete, replace) + 1
return mem[i][j]
def edit_distance_dp(s: str, t: str) -> int:
"""Edit distance: Dynamic programming"""
n, m = len(s), len(t)
dp = [[0] * (m + 1) for _ in range(n + 1)]
# State transition: first row and first column
for i in range(1, n + 1):
dp[i][0] = i
for j in range(1, m + 1):
dp[0][j] = j
# State transition: the rest of the rows and columns
for i in range(1, n + 1):
for j in range(1, m + 1):
if s[i - 1] == t[j - 1]:
# If the two characters are equal, skip these two characters
dp[i][j] = dp[i - 1][j - 1]
else:
# The minimum number of edits = the minimum number of edits from three operations (insert, remove, replace) + 1
dp[i][j] = min(dp[i][j - 1], dp[i - 1][j], dp[i - 1][j - 1]) + 1
return dp[n][m]
def edit_distance_dp_comp(s: str, t: str) -> int:
"""Edit distance: Space-optimized dynamic programming"""
n, m = len(s), len(t)
dp = [0] * (m + 1)
# State transition: first row
for j in range(1, m + 1):
dp[j] = j
# State transition: the rest of the rows
for i in range(1, n + 1):
# State transition: first column
leftup = dp[0] # Temporarily store dp[i-1, j-1]
dp[0] += 1
# State transition: the rest of the columns
for j in range(1, m + 1):
temp = dp[j]
if s[i - 1] == t[j - 1]:
# If the two characters are equal, skip these two characters
dp[j] = leftup
else:
# The minimum number of edits = the minimum number of edits from three operations (insert, remove, replace) + 1
dp[j] = min(dp[j - 1], dp[j], leftup) + 1
leftup = temp # Update for the next round of dp[i-1, j-1]
return dp[m]
"""Driver Code"""
if __name__ == "__main__":
s = "bag"
t = "pack"
n, m = len(s), len(t)
# Brute force search
res = edit_distance_dfs(s, t, n, m)
print(f"To change {s} to {t}, the minimum number of edits required is {res}")
# Memoized search
mem = [[-1] * (m + 1) for _ in range(n + 1)]
res = edit_distance_dfs_mem(s, t, mem, n, m)
print(f"To change {s} to {t}, the minimum number of edits required is {res}")
# Dynamic programming
res = edit_distance_dp(s, t)
print(f"To change {s} to {t}, the minimum number of edits required is {res}")
# Space-optimized dynamic programming
res = edit_distance_dp_comp(s, t)
print(f"To change {s} to {t}, the minimum number of edits required is {res}")