hello-algo/zh-hant/codes/ruby/chapter_computational_complexity/space_complexity.rb
Yudong Jin b2f0d4603d
Many bug fixes and improvements (#1270)
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2024-04-11 20:18:19 +08:00

92 lines
1.6 KiB
Ruby

=begin
File: space_complexity.rb
Created Time: 2024-03-30
Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
=end
require_relative '../utils/list_node'
require_relative '../utils/tree_node'
require_relative '../utils/print_util'
### 函式 ###
def function
# 執行某些操作
0
end
### 常數階 ###
def constant(n)
# 常數、變數、物件佔用 O(1) 空間
a = 0
nums = [0] * 10000
node = ListNode.new
# 迴圈中的變數佔用 O(1) 空間
(0...n).each { c = 0 }
# 迴圈中的函式佔用 O(1) 空間
(0...n).each { function }
end
### 線性階 ###
def linear(n)
# 長度為 n 的串列佔用 O(n) 空間
nums = Array.new(n, 0)
# 長度為 n 的雜湊表佔用 O(n) 空間
hmap = {}
for i in 0...n
hmap[i] = i.to_s
end
end
### 線性階(遞迴實現)###
def linear_recur(n)
puts "遞迴 n = #{n}"
return if n == 1
linear_recur(n - 1)
end
### 平方階 ###
def quadratic(n)
# 二維串列佔用 O(n^2) 空間
Array.new(n) { Array.new(n, 0) }
end
### 平方階(遞迴實現)###
def quadratic_recur(n)
return 0 unless n > 0
# 陣列 nums 長度為 n, n-1, ..., 2, 1
nums = Array.new(n, 0)
quadratic_recur(n - 1)
end
### 指數階(建立滿二元樹)###
def build_tree(n)
return if n == 0
TreeNode.new.tap do |root|
root.left = build_tree(n - 1)
root.right = build_tree(n - 1)
end
end
### Driver Code ###
if __FILE__ == $0
n = 5
# 常數階
constant(n)
# 線性階
linear(n)
linear_recur(n)
# 平方階
quadratic(n)
quadratic_recur(n)
# 指數階
root = build_tree(n)
print_tree(root)
end