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492a69ebca
* Re-implement merge sort function. * Replace vector with array for C. * fix
69 lines
1.8 KiB
C
69 lines
1.8 KiB
C
/**
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* File: subset_sum_i_naive.c
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* Created Time: 2023-07-28
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* Author: Gonglja (glj0@outlook.com)
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*/
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#include "../utils/common.h"
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#define MAX_SIZE 100
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#define MAX_RES_SIZE 100
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// 状态(子集)
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int state[MAX_SIZE];
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int stateSize = 0;
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// 结果列表(子集列表)
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int res[MAX_RES_SIZE][MAX_SIZE];
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int resColSizes[MAX_RES_SIZE];
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int resSize = 0;
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/* 回溯算法:子集和 I */
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void backtrack(int target, int total, int *choices, int choicesSize) {
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// 子集和等于 target 时,记录解
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if (total == target) {
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for (int i = 0; i < stateSize; i++) {
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res[resSize][i] = state[i];
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}
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resColSizes[resSize++] = stateSize;
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return;
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}
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// 遍历所有选择
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for (int i = 0; i < choicesSize; i++) {
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// 剪枝:若子集和超过 target ,则跳过该选择
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if (total + choices[i] > target) {
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continue;
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}
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// 尝试:做出选择,更新元素和 total
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state[stateSize++] = choices[i];
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// 进行下一轮选择
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backtrack(target, total + choices[i], choices, choicesSize);
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// 回退:撤销选择,恢复到之前的状态
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stateSize--;
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}
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}
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/* 求解子集和 I(包含重复子集) */
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void subsetSumINaive(int *nums, int numsSize, int target) {
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resSize = 0; // 初始化解的数量为0
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backtrack(target, 0, nums, numsSize);
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}
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/* Driver Code */
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int main() {
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int nums[] = {3, 4, 5};
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int numsSize = sizeof(nums) / sizeof(nums[0]);
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int target = 9;
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subsetSumINaive(nums, numsSize, target);
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printf("输入数组 nums = ");
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printArray(nums, numsSize);
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printf("target = %d\n", target);
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printf("所有和等于 %d 的子集 res = \n", target);
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for (int i = 0; i < resSize; i++) {
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printArray(res[i], resColSizes[i]);
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}
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return 0;
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}
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