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1c8b7ef559
* Replace 结点 with 节点 Update the footnotes in the figures * Update mindmap * Reduce the size of the mindmap.png
183 lines
5.3 KiB
Java
183 lines
5.3 KiB
Java
/**
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* File: binary_search_tree.cs
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* Created Time: 2022-12-23
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* Author: haptear (haptear@hotmail.com)
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*/
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using hello_algo.include;
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using NUnit.Framework;
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namespace hello_algo.chapter_tree;
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class BinarySearchTree
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{
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TreeNode? root;
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public BinarySearchTree(int[] nums)
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{
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Array.Sort(nums); // 排序数组
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root = buildTree(nums, 0, nums.Length - 1); // 构建二叉搜索树
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}
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/* 获取二叉树根节点 */
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public TreeNode? getRoot()
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{
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return root;
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}
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/* 构建二叉搜索树 */
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public TreeNode? buildTree(int[] nums, int i, int j)
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{
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if (i > j) return null;
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// 将数组中间节点作为根节点
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int mid = (i + j) / 2;
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TreeNode root = new TreeNode(nums[mid]);
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// 递归建立左子树和右子树
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root.left = buildTree(nums, i, mid - 1);
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root.right = buildTree(nums, mid + 1, j);
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return root;
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}
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/* 查找节点 */
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public TreeNode? search(int num)
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{
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TreeNode? cur = root;
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// 循环查找,越过叶节点后跳出
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while (cur != null)
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{
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// 目标节点在 cur 的右子树中
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if (cur.val < num) cur = cur.right;
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// 目标节点在 cur 的左子树中
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else if (cur.val > num) cur = cur.left;
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// 找到目标节点,跳出循环
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else break;
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}
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// 返回目标节点
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return cur;
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}
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/* 插入节点 */
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public TreeNode? insert(int num)
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{
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// 若树为空,直接提前返回
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if (root == null) return null;
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TreeNode? cur = root, pre = null;
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// 循环查找,越过叶节点后跳出
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while (cur != null)
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{
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// 找到重复节点,直接返回
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if (cur.val == num) return null;
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pre = cur;
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// 插入位置在 cur 的右子树中
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if (cur.val < num) cur = cur.right;
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// 插入位置在 cur 的左子树中
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else cur = cur.left;
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}
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// 插入节点 val
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TreeNode node = new TreeNode(num);
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if (pre != null)
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{
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if (pre.val < num) pre.right = node;
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else pre.left = node;
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}
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return node;
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}
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/* 删除节点 */
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public TreeNode? remove(int num)
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{
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// 若树为空,直接提前返回
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if (root == null) return null;
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TreeNode? cur = root, pre = null;
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// 循环查找,越过叶节点后跳出
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while (cur != null)
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{
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// 找到待删除节点,跳出循环
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if (cur.val == num) break;
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pre = cur;
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// 待删除节点在 cur 的右子树中
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if (cur.val < num) cur = cur.right;
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// 待删除节点在 cur 的左子树中
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else cur = cur.left;
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}
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// 若无待删除节点,则直接返回
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if (cur == null || pre == null) return null;
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// 子节点数量 = 0 or 1
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if (cur.left == null || cur.right == null)
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{
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// 当子节点数量 = 0 / 1 时, child = null / 该子节点
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TreeNode? child = cur.left != null ? cur.left : cur.right;
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// 删除节点 cur
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if (pre.left == cur)
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{
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pre.left = child;
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}
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else
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{
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pre.right = child;
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}
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}
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// 子节点数量 = 2
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else
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{
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// 获取中序遍历中 cur 的下一个节点
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TreeNode? nex = getInOrderNext(cur.right);
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if (nex != null)
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{
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int tmp = nex.val;
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// 递归删除节点 nex
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remove(nex.val);
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// 将 nex 的值复制给 cur
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cur.val = tmp;
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}
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}
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return cur;
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}
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/* 获取中序遍历中的下一个节点(仅适用于 root 有左子节点的情况) */
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private TreeNode? getInOrderNext(TreeNode? root)
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{
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if (root == null) return root;
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// 循环访问左子节点,直到叶节点时为最小节点,跳出
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while (root.left != null)
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{
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root = root.left;
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}
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return root;
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}
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}
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public class binary_search_tree
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{
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[Test]
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public void Test()
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{
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/* 初始化二叉搜索树 */
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int[] nums = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 };
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BinarySearchTree bst = new BinarySearchTree(nums);
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Console.WriteLine("\n初始化的二叉树为\n");
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PrintUtil.PrintTree(bst.getRoot());
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/* 查找节点 */
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TreeNode? node = bst.search(7);
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Console.WriteLine("\n查找到的节点对象为 " + node + ",节点值 = " + node.val);
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/* 插入节点 */
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node = bst.insert(16);
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Console.WriteLine("\n插入节点 16 后,二叉树为\n");
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PrintUtil.PrintTree(bst.getRoot());
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/* 删除节点 */
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bst.remove(1);
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Console.WriteLine("\n删除节点 1 后,二叉树为\n");
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PrintUtil.PrintTree(bst.getRoot());
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bst.remove(2);
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Console.WriteLine("\n删除节点 2 后,二叉树为\n");
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PrintUtil.PrintTree(bst.getRoot());
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bst.remove(4);
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Console.WriteLine("\n删除节点 4 后,二叉树为\n");
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PrintUtil.PrintTree(bst.getRoot());
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}
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}
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