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3f03663d2e
* add the section of the introduction to dynamic programming * add a code comments.
41 lines
No EOL
1.1 KiB
Java
41 lines
No EOL
1.1 KiB
Java
/**
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* File: climbing_stairs_dfs_mem.java
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* Created Time: 2023-06-30
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_dynamic_programming;
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import java.util.Arrays;
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public class climbing_stairs_dfs_mem {
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/* 记忆化搜索 */
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public static int dfs(int i, int[] mem) {
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// 已知 dp[1] 和 dp[2] ,返回之
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if (i == 1 || i == 2)
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return i;
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// 若存在记录 dp[i] ,则直接返回之
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if (mem[i] != -1)
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return mem[i];
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// dp[i] = dp[i-1] + dp[i-2]
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int count = dfs(i - 1, mem) + dfs(i - 2, mem);
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// 记录 dp[i]
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mem[i] = count;
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return count;
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}
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/* 爬楼梯:记忆化搜索 */
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public static int climbingStairsDFSMem(int n) {
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// mem[i] 记录爬到第 i 阶的方案总数,-1 代表无记录
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int[] mem = new int[n + 1];
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Arrays.fill(mem, -1);
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return dfs(n, mem);
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}
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public static void main(String[] args) {
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int n = 9;
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int res = climbingStairsDFSMem(n);
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System.out.println(String.format("爬 %d 阶楼梯共有 %d 种方案", n, res));
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}
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} |