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* Modify method name to PascalCase(array and linked list) * Modify method name to PascalCase(backtracking) * Modify method name to PascalCase(computational complexity) * Modify method name to PascalCase(divide and conquer) * Modify method name to PascalCase(dynamic programming) * Modify method name to PascalCase(graph) * Modify method name to PascalCase(greedy) * Modify method name to PascalCase(hashing) * Modify method name to PascalCase(heap) * Modify method name to PascalCase(searching) * Modify method name to PascalCase(sorting) * Modify method name to PascalCase(stack and queue) * Modify method name to PascalCase(tree) * local check
53 lines
1.9 KiB
C#
53 lines
1.9 KiB
C#
/**
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* File: subset_sum_i_naive.cs
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* Created Time: 2023-06-25
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* Author: hpstory (hpstory1024@163.com)
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*/
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namespace hello_algo.chapter_backtracking;
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public class subset_sum_i_naive {
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/* 回溯算法:子集和 I */
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public static void Backtrack(List<int> state, int target, int total, int[] choices, List<List<int>> res) {
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// 子集和等于 target 时,记录解
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if (total == target) {
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res.Add(new List<int>(state));
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return;
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}
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// 遍历所有选择
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for (int i = 0; i < choices.Length; i++) {
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// 剪枝:若子集和超过 target ,则跳过该选择
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if (total + choices[i] > target) {
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continue;
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}
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// 尝试:做出选择,更新元素和 total
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state.Add(choices[i]);
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// 进行下一轮选择
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Backtrack(state, target, total + choices[i], choices, res);
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// 回退:撤销选择,恢复到之前的状态
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state.RemoveAt(state.Count - 1);
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}
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}
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/* 求解子集和 I(包含重复子集) */
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public static List<List<int>> SubsetSumINaive(int[] nums, int target) {
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List<int> state = new(); // 状态(子集)
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int total = 0; // 子集和
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List<List<int>> res = new(); // 结果列表(子集列表)
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Backtrack(state, target, total, nums, res);
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return res;
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}
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[Test]
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public void Test() {
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int[] nums = { 3, 4, 5 };
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int target = 9;
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List<List<int>> res = SubsetSumINaive(nums, target);
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Console.WriteLine("输入数组 nums = " + string.Join(", ", nums) + ", target = " + target);
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Console.WriteLine("所有和等于 " + target + " 的子集 res = ");
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foreach (var subset in res) {
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PrintUtil.PrintList(subset);
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}
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Console.WriteLine("请注意,该方法输出的结果包含重复集合");
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}
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}
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