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431a0f6caf
computational complexity, sorting, searching. 2. Corrected some mistakes. 3. Update README.
57 lines
1.7 KiB
Java
57 lines
1.7 KiB
Java
/*
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* File: leetcode_two_sum.java
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* Created Time: 2022-11-25
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_computational_complexity;
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import java.util.*;
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class SolutionBruteForce {
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public int[] twoSum(int[] nums, int target) {
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int size = nums.length;
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// 两层循环,时间复杂度 O(n^2)
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for (int i = 0; i < size - 1; i++) {
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for (int j = i + 1; j < size; j++) {
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if (nums[i] + nums[j] == target)
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return new int[] { i, j };
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}
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}
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return new int[0];
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}
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}
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class SolutionHashMap {
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public int[] twoSum(int[] nums, int target) {
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int size = nums.length;
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// 辅助哈希表,空间复杂度 O(n)
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Map<Integer, Integer> dic = new HashMap<>();
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// 单层循环,时间复杂度 O(n)
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for (int i = 0; i < size; i++) {
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if (dic.containsKey(target - nums[i])) {
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return new int[] { dic.get(target - nums[i]), i };
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}
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dic.put(nums[i], i);
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}
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return new int[0];
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}
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}
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public class leetcode_two_sum {
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public static void main(String[] args) {
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// ======= Test Case =======
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int[] nums = { 2,7,11,15 };
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int target = 9;
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// ====== Driver Code ======
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// 方法一
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SolutionBruteForce slt1 = new SolutionBruteForce();
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int[] res = slt1.twoSum(nums, target);
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System.out.println("方法一 res = " + Arrays.toString(res));
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// 方法二
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SolutionHashMap slt2 = new SolutionHashMap();
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res = slt2.twoSum(nums, target);
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System.out.println("方法二 res = " + Arrays.toString(res));
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}
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}
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