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* Modify method name to PascalCase(array and linked list) * Modify method name to PascalCase(backtracking) * Modify method name to PascalCase(computational complexity) * Modify method name to PascalCase(divide and conquer) * Modify method name to PascalCase(dynamic programming) * Modify method name to PascalCase(graph) * Modify method name to PascalCase(greedy) * Modify method name to PascalCase(hashing) * Modify method name to PascalCase(heap) * Modify method name to PascalCase(searching) * Modify method name to PascalCase(sorting) * Modify method name to PascalCase(stack and queue) * Modify method name to PascalCase(tree) * local check
76 lines
2.7 KiB
C#
76 lines
2.7 KiB
C#
/**
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* File: n_queens.cs
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* Created Time: 2023-05-04
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* Author: hpstory (hpstory1024@163.com)
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*/
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namespace hello_algo.chapter_backtracking;
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public class n_queens {
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/* 回溯算法:N 皇后 */
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static void Backtrack(int row, int n, List<List<string>> state, List<List<List<string>>> res,
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bool[] cols, bool[] diags1, bool[] diags2) {
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// 当放置完所有行时,记录解
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if (row == n) {
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List<List<string>> copyState = new();
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foreach (List<string> sRow in state) {
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copyState.Add(new List<string>(sRow));
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}
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res.Add(copyState);
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return;
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}
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// 遍历所有列
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for (int col = 0; col < n; col++) {
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// 计算该格子对应的主对角线和副对角线
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int diag1 = row - col + n - 1;
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int diag2 = row + col;
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// 剪枝:不允许该格子所在列、主对角线、副对角线存在皇后
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if (!cols[col] && !diags1[diag1] && !diags2[diag2]) {
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// 尝试:将皇后放置在该格子
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state[row][col] = "Q";
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cols[col] = diags1[diag1] = diags2[diag2] = true;
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// 放置下一行
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Backtrack(row + 1, n, state, res, cols, diags1, diags2);
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// 回退:将该格子恢复为空位
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state[row][col] = "#";
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cols[col] = diags1[diag1] = diags2[diag2] = false;
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}
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}
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}
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/* 求解 N 皇后 */
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static List<List<List<string>>> NQueens(int n) {
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// 初始化 n*n 大小的棋盘,其中 'Q' 代表皇后,'#' 代表空位
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List<List<string>> state = new();
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for (int i = 0; i < n; i++) {
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List<string> row = new();
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for (int j = 0; j < n; j++) {
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row.Add("#");
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}
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state.Add(row);
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}
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bool[] cols = new bool[n]; // 记录列是否有皇后
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bool[] diags1 = new bool[2 * n - 1]; // 记录主对角线是否有皇后
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bool[] diags2 = new bool[2 * n - 1]; // 记录副对角线是否有皇后
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List<List<List<string>>> res = new();
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Backtrack(0, n, state, res, cols, diags1, diags2);
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return res;
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}
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[Test]
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public void Test() {
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int n = 4;
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List<List<List<string>>> res = NQueens(n);
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Console.WriteLine("输入棋盘长宽为 " + n);
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Console.WriteLine("皇后放置方案共有 " + res.Count + " 种");
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foreach (List<List<string>> state in res) {
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Console.WriteLine("--------------------");
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foreach (List<string> row in state) {
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PrintUtil.PrintList(row);
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}
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}
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}
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}
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