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120 lines
3.6 KiB
C
120 lines
3.6 KiB
C
/**
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* File: min_path_sum.c
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* Created Time: 2023-10-02
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* Author: Zuoxun (845242523@qq.com)
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*/
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#include "../utils/common.h"
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/* 求最小值 */
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int min(int a, int b) {
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return a < b ? a : b;
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}
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/* 最小路径和:暴力搜索 */
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int minPathSumDFS(int gridCols, int grid[][gridCols], int i, int j) {
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// 若为左上角单元格,则终止搜索
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if (i == 0 && j == 0) {
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return grid[0][0];
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}
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// 若行列索引越界,则返回 +∞ 代价
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if (i < 0 || j < 0) {
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return INT_MAX;
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}
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// 计算从左上角到 (i-1, j) 和 (i, j-1) 的最小路径代价
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int up = minPathSumDFS(gridCols, grid, i - 1, j);
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int left = minPathSumDFS(gridCols, grid, i, j - 1);
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// 返回从左上角到 (i, j) 的最小路径代价
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return min(left, up) != INT_MAX ? min(left, up) + grid[i][j] : INT_MAX;
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}
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/* 最小路径和:记忆化搜索 */
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int minPathSumDFSMem(int gridCols, int grid[][gridCols], int mem[][gridCols], int i, int j) {
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// 若为左上角单元格,则终止搜索
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if (i == 0 && j == 0) {
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return grid[0][0];
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}
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// 若行列索引越界,则返回 +∞ 代价
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if (i < 0 || j < 0) {
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return INT_MAX;
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}
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// 若已有记录,则直接返回
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if (mem[i][j] != -1) {
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return mem[i][j];
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}
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// 左边和上边单元格的最小路径代价
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int up = minPathSumDFSMem(gridCols, grid, mem, i - 1, j);
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int left = minPathSumDFSMem(gridCols, grid, mem, i, j - 1);
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// 记录并返回左上角到 (i, j) 的最小路径代价
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mem[i][j] = min(left, up) != INT_MAX ? min(left, up) + grid[i][j] : INT_MAX;
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return mem[i][j];
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}
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/* 最小路径和:动态规划 */
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int minPathSumDP(int gridCols, int grid[][gridCols], int n, int m) {
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// 初始化 dp 表
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int dp[n][m];
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dp[0][0] = grid[0][0];
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// 状态转移:首行
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for (int j = 1; j < m; j++) {
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dp[0][j] = dp[0][j - 1] + grid[0][j];
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}
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// 状态转移:首列
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for (int i = 1; i < n; i++) {
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dp[i][0] = dp[i - 1][0] + grid[i][0];
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}
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// 状态转移:其余行列
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for (int i = 1; i < n; i++) {
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for (int j = 1; j < m; j++) {
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dp[i][j] = min(dp[i][j - 1], dp[i - 1][j]) + grid[i][j];
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}
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}
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return dp[n - 1][m - 1];
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}
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/* 最小路径和:空间优化后的动态规划 */
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int minPathSumDPComp(int gridCols, int grid[][gridCols], int n, int m) {
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// 初始化 dp 表
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int dp[m];
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// 状态转移:首行
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dp[0] = grid[0][0];
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for (int j = 1; j < m; j++) {
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dp[j] = dp[j - 1] + grid[0][j];
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}
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// 状态转移:其余行
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for (int i = 1; i < n; i++) {
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// 状态转移:首列
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dp[0] = dp[0] + grid[i][0];
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// 状态转移:其余列
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for (int j = 1; j < m; j++) {
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dp[j] = min(dp[j - 1], dp[j]) + grid[i][j];
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}
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}
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return dp[m - 1];
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}
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/* Driver Code */
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int main() {
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int grid[][4] = {{1, 3, 1, 5}, {2, 2, 4, 2}, {5, 3, 2, 1}, {4, 3, 5, 2}};
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int n = sizeof(grid) / sizeof(grid[0]), m = sizeof(grid[0]) / sizeof(grid[0][0]);
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// 暴力搜索
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int res = minPathSumDFS(m, grid, n - 1, m - 1);
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printf("从左上角到右下角的最小路径和为 %d\n", res);
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// 记忆化搜索
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int mem[n][m];
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memset(mem, -1, sizeof(mem));
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res = minPathSumDFSMem(m, grid, mem, n - 1, m - 1);
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printf("从左上角到右下角的最小路径和为 %d\n", res);
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// 动态规划
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res = minPathSumDP(m, grid, n, m);
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printf("从左上角到右下角的最小路径和为 %d\n", res);
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// 空间优化后的动态规划
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res = minPathSumDPComp(m, grid, n, m);
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printf("从左上角到右下角的最小路径和为 %d\n", res);
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return 0;
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}
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