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f62256bee1
* Modify method name to PascalCase(array and linked list) * Modify method name to PascalCase(backtracking) * Modify method name to PascalCase(computational complexity) * Modify method name to PascalCase(divide and conquer) * Modify method name to PascalCase(dynamic programming) * Modify method name to PascalCase(graph) * Modify method name to PascalCase(greedy) * Modify method name to PascalCase(hashing) * Modify method name to PascalCase(heap) * Modify method name to PascalCase(searching) * Modify method name to PascalCase(sorting) * Modify method name to PascalCase(stack and queue) * Modify method name to PascalCase(tree) * local check
78 lines
2 KiB
C#
78 lines
2 KiB
C#
/**
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* File: recursion.cs
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* Created Time: 2023-08-28
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* Author: hpstory (hpstory1024@163.com)
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*/
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namespace hello_algo.chapter_computational_complexity;
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public class recursion {
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/* 递归 */
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public int Recur(int n) {
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// 终止条件
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if (n == 1)
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return 1;
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// 递:递归调用
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int res = Recur(n - 1);
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// 归:返回结果
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return n + res;
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}
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/* 使用迭代模拟递归 */
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public static int ForLoopRecur(int n) {
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// 使用一个显式的栈来模拟系统调用栈
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Stack<int> stack = new();
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int res = 0;
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// 递:递归调用
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for (int i = n; i > 0; i--) {
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// 通过“入栈操作”模拟“递”
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stack.Push(i);
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}
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// 归:返回结果
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while (stack.Count > 0) {
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// 通过“出栈操作”模拟“归”
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res += stack.Pop();
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}
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// res = 1+2+3+...+n
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return res;
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}
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/* 尾递归 */
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public int TailRecur(int n, int res) {
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// 终止条件
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if (n == 0)
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return res;
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// 尾递归调用
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return TailRecur(n - 1, res + n);
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}
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/* 斐波那契数列:递归 */
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public int Fib(int n) {
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// 终止条件 f(1) = 0, f(2) = 1
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if (n == 1 || n == 2)
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return n - 1;
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// 递归调用 f(n) = f(n-1) + f(n-2)
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int res = Fib(n - 1) + Fib(n - 2);
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// 返回结果 f(n)
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return res;
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}
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/* Driver Code */
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[Test]
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public void Test() {
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int n = 5;
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int res;
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res = Recur(n);
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Console.WriteLine("\n递归函数的求和结果 res = " + res);
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res = ForLoopRecur(n);
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Console.WriteLine("\n使用迭代模拟递归求和结果 res = " + res);
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res = TailRecur(n, 0);
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Console.WriteLine("\n尾递归函数的求和结果 res = " + res);
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res = Fib(n);
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Console.WriteLine("\n斐波那契数列的第 " + n + " 项为 " + res);
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}
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}
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