hello-algo/codes/kotlin/chapter_computational_complexity/space_complexity.kt
curtishd 2655a2f66a
Simplify kotlin code and improve code readability (#1198)
* Add kotlin code block for chapter_hashing

* Add kotlin code block for chapter_heap.

* Add kotlin code block for chapter_stack_and_queue and chapter_tree

* fix indentation

* Update binary_tree.md

* style(kotlin): simplify code and improve readability.

* simplify kt code for chapter_computational_complexity.

* style(kotlin): replace ArrayList with MutableList.

* Update subset_sum_i.kt

Use kotlin api instead of java.

* Update subset_sum_ii.kt

use kotlin api instead of java

* style(kotlin): replace ArrayList with mutablelist.

---------

Co-authored-by: Yudong Jin <krahets@163.com>
2024-04-07 01:31:58 +08:00

109 lines
No EOL
2.3 KiB
Kotlin

/**
* File: space_complexity.kt
* Created Time: 2024-01-25
* Author: curtishd (1023632660@qq.com)
*/
package chapter_computational_complexity.space_complexity
import utils.ListNode
import utils.TreeNode
import utils.printTree
/* 函数 */
fun function(): Int {
// 执行某些操作
return 0
}
/* 常数阶 */
fun constant(n: Int) {
// 常量、变量、对象占用 O(1) 空间
val a = 0
var b = 0
val nums = Array(10000) { 0 }
val node = ListNode(0)
// 循环中的变量占用 O(1) 空间
for (i in 0..<n) {
val c = 0
}
// 循环中的函数占用 O(1) 空间
for (i in 0..<n) {
function()
}
}
/* 线性阶 */
fun linear(n: Int) {
// 长度为 n 的数组占用 O(n) 空间
val nums = Array(n) { 0 }
// 长度为 n 的列表占用 O(n) 空间
val nodes = mutableListOf<ListNode>()
for (i in 0..<n) {
nodes.add(ListNode(i))
}
// 长度为 n 的哈希表占用 O(n) 空间
val map = mutableMapOf<Int, String>()
for (i in 0..<n) {
map[i] = i.toString()
}
}
/* 线性阶(递归实现) */
fun linearRecur(n: Int) {
println("递归 n = $n")
if (n == 1)
return
linearRecur(n - 1)
}
/* 平方阶 */
fun quadratic(n: Int) {
// 矩阵占用 O(n^2) 空间
val numMatrix = arrayOfNulls<Array<Int>?>(n)
// 二维列表占用 O(n^2) 空间
val numList = mutableListOf<MutableList<Int>>()
for (i in 0..<n) {
val tmp = mutableListOf<Int>()
for (j in 0..<n) {
tmp.add(0)
}
numList.add(tmp)
}
}
/* 平方阶(递归实现) */
tailrec fun quadraticRecur(n: Int): Int {
if (n <= 0)
return 0
// 数组 nums 长度为 n, n-1, ..., 2, 1
val nums = Array(n) { 0 }
println("递归 n = $n 中的 nums 长度 = ${nums.size}")
return quadraticRecur(n - 1)
}
/* 指数阶(建立满二叉树) */
fun buildTree(n: Int): TreeNode? {
if (n == 0)
return null
val root = TreeNode(0)
root.left = buildTree(n - 1)
root.right = buildTree(n - 1)
return root
}
/* Driver Code */
fun main() {
val n = 5
// 常数阶
constant(n)
// 线性阶
linear(n)
linearRecur(n)
// 平方阶
quadratic(n)
quadraticRecur(n)
// 指数阶
val root = buildTree(n)
printTree(root)
}