hello-algo/en/codes/python/chapter_searching/binary_search.py
rongyi 21be3fdaf8
[Rust] Normalize mid calculation in case overflow (#1363)
* Normalize mid calculate in case overflow

* Change ALL language

* Update merge_sort.py

* Update merge_sort.zig

* Update binary_search_tree.zig

* Update binary_search_recur.py

---------

Co-authored-by: Yudong Jin <krahets@163.com>
2024-05-18 18:19:19 +08:00

52 lines
2.2 KiB
Python

"""
File: binary_search.py
Created Time: 2022-11-26
Author: timi (xisunyy@163.com)
"""
def binary_search(nums: list[int], target: int) -> int:
"""Binary search (double closed interval)"""
# Initialize double closed interval [0, n-1], i.e., i, j point to the first element and last element of the array respectively
i, j = 0, len(nums) - 1
# Loop until the search interval is empty (when i > j, it is empty)
while i <= j:
# Theoretically, Python's numbers can be infinitely large (depending on memory size), so there is no need to consider large number overflow
m = i + (j - i) // 2 # Calculate midpoint index m
if nums[m] < target:
i = m + 1 # This situation indicates that target is in the interval [m+1, j]
elif nums[m] > target:
j = m - 1 # This situation indicates that target is in the interval [i, m-1]
else:
return m # Found the target element, thus return its index
return -1 # Did not find the target element, thus return -1
def binary_search_lcro(nums: list[int], target: int) -> int:
"""Binary search (left closed right open interval)"""
# Initialize left closed right open interval [0, n), i.e., i, j point to the first element and the last element +1 of the array respectively
i, j = 0, len(nums)
# Loop until the search interval is empty (when i = j, it is empty)
while i < j:
m = i + (j - i) // 2 # Calculate midpoint index m
if nums[m] < target:
i = m + 1 # This situation indicates that target is in the interval [m+1, j)
elif nums[m] > target:
j = m # This situation indicates that target is in the interval [i, m)
else:
return m # Found the target element, thus return its index
return -1 # Did not find the target element, thus return -1
"""Driver Code"""
if __name__ == "__main__":
target = 6
nums = [1, 3, 6, 8, 12, 15, 23, 26, 31, 35]
# Binary search (double closed interval)
index = binary_search(nums, target)
print("Index of target element 6 =", index)
# Binary search (left closed right open interval)
index = binary_search_lcro(nums, target)
print("Index of target element 6 =", index)