hello-algo/en/codes/python/chapter_computational_complexity/time_complexity.py
Yudong Jin 1c0f350ad6
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2024-05-06 05:21:51 +08:00

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Python

"""
File: time_complexity.py
Created Time: 2022-11-25
Author: krahets (krahets@163.com)
"""
def constant(n: int) -> int:
"""Constant complexity"""
count = 0
size = 100000
for _ in range(size):
count += 1
return count
def linear(n: int) -> int:
"""Linear complexity"""
count = 0
for _ in range(n):
count += 1
return count
def array_traversal(nums: list[int]) -> int:
"""Linear complexity (traversing an array)"""
count = 0
# Loop count is proportional to the length of the array
for num in nums:
count += 1
return count
def quadratic(n: int) -> int:
"""Quadratic complexity"""
count = 0
# Loop count is squared in relation to the data size n
for i in range(n):
for j in range(n):
count += 1
return count
def bubble_sort(nums: list[int]) -> int:
"""Quadratic complexity (bubble sort)"""
count = 0 # Counter
# Outer loop: unsorted range is [0, i]
for i in range(len(nums) - 1, 0, -1):
# Inner loop: swap the largest element in the unsorted range [0, i] to the right end of the range
for j in range(i):
if nums[j] > nums[j + 1]:
# Swap nums[j] and nums[j + 1]
tmp: int = nums[j]
nums[j] = nums[j + 1]
nums[j + 1] = tmp
count += 3 # Element swap includes 3 individual operations
return count
def exponential(n: int) -> int:
"""Exponential complexity (loop implementation)"""
count = 0
base = 1
# Cells split into two every round, forming the sequence 1, 2, 4, 8, ..., 2^(n-1)
for _ in range(n):
for _ in range(base):
count += 1
base *= 2
# count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
return count
def exp_recur(n: int) -> int:
"""Exponential complexity (recursive implementation)"""
if n == 1:
return 1
return exp_recur(n - 1) + exp_recur(n - 1) + 1
def logarithmic(n: int) -> int:
"""Logarithmic complexity (loop implementation)"""
count = 0
while n > 1:
n = n / 2
count += 1
return count
def log_recur(n: int) -> int:
"""Logarithmic complexity (recursive implementation)"""
if n <= 1:
return 0
return log_recur(n / 2) + 1
def linear_log_recur(n: int) -> int:
"""Linear logarithmic complexity"""
if n <= 1:
return 1
count: int = linear_log_recur(n // 2) + linear_log_recur(n // 2)
for _ in range(n):
count += 1
return count
def factorial_recur(n: int) -> int:
"""Factorial complexity (recursive implementation)"""
if n == 0:
return 1
count = 0
# From 1 split into n
for _ in range(n):
count += factorial_recur(n - 1)
return count
"""Driver Code"""
if __name__ == "__main__":
# Can modify n to experience the trend of operation count changes under various complexities
n = 8
print("Input data size n =", n)
count: int = constant(n)
print("Constant complexity operation count =", count)
count: int = linear(n)
print("Linear complexity operation count =", count)
count: int = array_traversal([0] * n)
print("Linear complexity (traversing an array) operation count =", count)
count: int = quadratic(n)
print("Quadratic complexity operation count =", count)
nums = [i for i in range(n, 0, -1)] # [n, n-1, ..., 2, 1]
count: int = bubble_sort(nums)
print("Quadratic complexity (bubble sort) operation count =", count)
count: int = exponential(n)
print("Exponential complexity (loop implementation) operation count =", count)
count: int = exp_recur(n)
print("Exponential complexity (recursive implementation) operation count =", count)
count: int = logarithmic(n)
print("Logarithmic complexity (loop implementation) operation count =", count)
count: int = log_recur(n)
print("Logarithmic complexity (recursive implementation) operation count =", count)
count: int = linear_log_recur(n)
print("Linear logarithmic complexity (recursive implementation) operation count =", count)
count: int = factorial_recur(n)
print("Factorial complexity (recursive implementation) operation count =", count)