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2655a2f66a
* Add kotlin code block for chapter_hashing * Add kotlin code block for chapter_heap. * Add kotlin code block for chapter_stack_and_queue and chapter_tree * fix indentation * Update binary_tree.md * style(kotlin): simplify code and improve readability. * simplify kt code for chapter_computational_complexity. * style(kotlin): replace ArrayList with MutableList. * Update subset_sum_i.kt Use kotlin api instead of java. * Update subset_sum_ii.kt use kotlin api instead of java * style(kotlin): replace ArrayList with mutablelist. --------- Co-authored-by: Yudong Jin <krahets@163.com>
85 lines
No EOL
2.5 KiB
Kotlin
85 lines
No EOL
2.5 KiB
Kotlin
/**
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* File: n_queens.kt
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* Created Time: 2024-01-25
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* Author: curtishd (1023632660@qq.com)
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*/
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package chapter_backtracking.n_queens
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/* 回溯算法：n 皇后 */
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fun backtrack(
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row: Int,
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n: Int,
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state: MutableList<MutableList<String>>,
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res: MutableList<MutableList<MutableList<String>>?>,
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cols: BooleanArray,
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diags1: BooleanArray,
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diags2: BooleanArray
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) {
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// 当放置完所有行时，记录解
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if (row == n) {
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val copyState = mutableListOf<MutableList<String>>()
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for (sRow in state) {
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copyState.add(sRow.toMutableList())
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}
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res.add(copyState)
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return
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}
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// 遍历所有列
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for (col in 0..<n) {
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// 计算该格子对应的主对角线和次对角线
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val diag1 = row - col + n - 1
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val diag2 = row + col
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// 剪枝：不允许该格子所在列、主对角线、次对角线上存在皇后
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if (!cols[col] && !diags1[diag1] && !diags2[diag2]) {
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// 尝试：将皇后放置在该格子
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state[row][col] = "Q"
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diags2[diag2] = true
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diags1[diag1] = diags2[diag2]
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cols[col] = diags1[diag1]
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// 放置下一行
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backtrack(row + 1, n, state, res, cols, diags1, diags2)
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// 回退：将该格子恢复为空位
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state[row][col] = "#"
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diags2[diag2] = false
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diags1[diag1] = diags2[diag2]
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cols[col] = diags1[diag1]
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}
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}
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}
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/* 求解 n 皇后 */
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fun nQueens(n: Int): MutableList<MutableList<MutableList<String>>?> {
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// 初始化 n*n 大小的棋盘，其中 'Q' 代表皇后，'#' 代表空位
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val state = mutableListOf<MutableList<String>>()
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for (i in 0..<n) {
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val row = mutableListOf<String>()
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for (j in 0..<n) {
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row.add("#")
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}
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state.add(row)
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}
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val cols = BooleanArray(n) // 记录列是否有皇后
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val diags1 = BooleanArray(2 * n - 1) // 记录主对角线上是否有皇后
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val diags2 = BooleanArray(2 * n - 1) // 记录次对角线上是否有皇后
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val res = mutableListOf<MutableList<MutableList<String>>?>()
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backtrack(0, n, state, res, cols, diags1, diags2)
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return res
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}
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/* Driver Code */
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fun main() {
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val n = 4
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val res = nQueens(n)
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println("输入棋盘长宽为 $n")
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println("皇后放置方案共有 ${res.size} 种")
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for (state in res) {
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println("--------------------")
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for (row in state!!) {
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println(row)
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}
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}
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} |