hello-algo/codes/go/chapter_tree/array_binary_tree.go
Yudong Jin ddd375af20
feat: Add visualizing code blocks based on the pythontutor (#1029)
* Update copyright

* Update the Python code

* Fix the code comments in ArrayBinaryTree

* Fix the code comments in ArrayBinaryTree

* Roll back time_comlexity.py

* Add the visualizing code(pythontutor) blocks to the chapter complexity, data structure, array and linked list, stack and queue, hash table, and backtracking

* Fix the code comments
2024-01-07 04:04:01 +08:00

101 lines
2 KiB
Go

// File: array_binary_tree.go
// Created Time: 2023-07-24
// Author: Reanon (793584285@qq.com)
package chapter_tree
/* 数组表示下的二叉树类 */
type arrayBinaryTree struct {
tree []any
}
/* 构造方法 */
func newArrayBinaryTree(arr []any) *arrayBinaryTree {
return &arrayBinaryTree{
tree: arr,
}
}
/* 列表容量 */
func (abt *arrayBinaryTree) size() int {
return len(abt.tree)
}
/* 获取索引为 i 节点的值 */
func (abt *arrayBinaryTree) val(i int) any {
// 若索引越界,则返回 null ,代表空位
if i < 0 || i >= abt.size() {
return nil
}
return abt.tree[i]
}
/* 获取索引为 i 节点的左子节点的索引 */
func (abt *arrayBinaryTree) left(i int) int {
return 2*i + 1
}
/* 获取索引为 i 节点的右子节点的索引 */
func (abt *arrayBinaryTree) right(i int) int {
return 2*i + 2
}
/* 获取索引为 i 节点的父节点的索引 */
func (abt *arrayBinaryTree) parent(i int) int {
return (i - 1) / 2
}
/* 层序遍历 */
func (abt *arrayBinaryTree) levelOrder() []any {
var res []any
// 直接遍历数组
for i := 0; i < abt.size(); i++ {
if abt.val(i) != nil {
res = append(res, abt.val(i))
}
}
return res
}
/* 深度优先遍历 */
func (abt *arrayBinaryTree) dfs(i int, order string, res *[]any) {
// 若为空位,则返回
if abt.val(i) == nil {
return
}
// 前序遍历
if order == "pre" {
*res = append(*res, abt.val(i))
}
abt.dfs(abt.left(i), order, res)
// 中序遍历
if order == "in" {
*res = append(*res, abt.val(i))
}
abt.dfs(abt.right(i), order, res)
// 后序遍历
if order == "post" {
*res = append(*res, abt.val(i))
}
}
/* 前序遍历 */
func (abt *arrayBinaryTree) preOrder() []any {
var res []any
abt.dfs(0, "pre", &res)
return res
}
/* 中序遍历 */
func (abt *arrayBinaryTree) inOrder() []any {
var res []any
abt.dfs(0, "in", &res)
return res
}
/* 后序遍历 */
func (abt *arrayBinaryTree) postOrder() []any {
var res []any
abt.dfs(0, "post", &res)
return res
}