/*
 * File: preorder_traversal_iii_compact.rs
 * Created Time: 2023-07-15
 * Author: sjinzh (sjinzh@gmail.com)
 */

 include!("../include/include.rs");

use std::{cell::RefCell, rc::Rc};
use tree_node::{vec_to_tree, TreeNode};

/* 前序遍历：例题三 */
fn pre_order(res: &mut Vec<Vec<Rc<RefCell<TreeNode>>>>, path: &mut Vec<Rc<RefCell<TreeNode>>>, root: Option<Rc<RefCell<TreeNode>>>) {
    // 剪枝
    if root.is_none() || root.as_ref().unwrap().borrow().val == 3 {
        return;
    }
    if let Some(node) = root {
        // 尝试
        path.push(node.clone());
        if node.borrow().val == 7 {
            // 记录解
            res.push(path.clone());
        }
        pre_order(res, path, node.borrow().left.clone());
        pre_order(res, path, node.borrow().right.clone());
        // 回退
        path.remove(path.len() -  1);
    }
}

/* Driver Code */
pub fn main() {
    let root = vec_to_tree([1, 7, 3, 4, 5, 6, 7].map(|x| Some(x)).to_vec());
    println!("初始化二叉树");
    print_util::print_tree(root.as_ref().unwrap());

    // 前序遍历
    let mut path = Vec::new();
    let mut res = Vec::new();
    pre_order(&mut res, &mut path, root);

    println!("\n输出所有根节点到节点 7 的路径，且路径中不包含值为 3 的节点");
    for path in res {
        let mut vals = Vec::new();
        for node in path {
            vals.push(node.borrow().val)
        }
        println!("{:?}", vals);
    }
}