/** * File: preorder_traversal_iii_template.cpp * Created Time: 2023-04-16 * Author: Krahets (krahets@163.com) */ #include "../include/include.hpp" /* 判断当前状态是否为解 */ bool isSolution(vector &state) { return !state.empty() && state.back()->val == 7; } /* 记录解 */ void recordSolution(vector &state, vector> &res) { res.push_back(state); } /* 判断在当前状态下,该选择是否合法 */ bool isValid(vector &state, TreeNode *choice) { return choice != nullptr && choice->val != 3; } /* 更新状态 */ void makeChoice(vector &state, TreeNode *choice) { state.push_back(choice); } /* 恢复状态 */ void undoChoice(vector &state, TreeNode *choice) { state.pop_back(); } /* 回溯算法:例题三 */ void backtrack(vector &state, vector &choices, vector> &res) { // 检查是否为解 if (isSolution(state)) { // 记录解 recordSolution(state, res); return; } // 遍历所有选择 for (TreeNode *choice : choices) { // 剪枝:检查选择是否合法 if (isValid(state, choice)) { // 尝试:做出选择,更新状态 makeChoice(state, choice); vector nextChoices{choice->left, choice->right}; backtrack(state, nextChoices, res); // 回退:撤销选择,恢复到之前的状态 undoChoice(state, choice); } } } /* Driver Code */ int main() { TreeNode *root = vecToTree(vector{1, 7, 3, 4, 5, 6, 7}); cout << "\n初始化二叉树" << endl; printTree(root); // 回溯算法 vector state; vector choices = {root}; vector> res; backtrack(state, choices, res); cout << "\n输出所有根节点到节点 7 的路径,要求路径中不包含值为 3 的节点" << endl; for (vector &path : res) { vector vals; for (TreeNode *node : path) { vals.push_back(node->val); } printVector(vals); } }