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Update quick_sort.js

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Fix indentation
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Yudong Jin 2022-12-01 22:38:01 +08:00 committed by GitHub
parent 7eea137c28
commit be8a586768
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1 changed files with 19 additions and 19 deletions
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38
codes/javascript/chapter_sorting/quick_sort.js
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@ -17,29 +17,29 @@ class QuickSort {
partition(nums, left, right){
// 以 nums[left] 作为基准数
let i = left, j = right
while(i < j){
while(i < j && nums[j] >= nums[left]){
j -= 1 // 从右向左找首个小于基准数的元素
}
while(i < j && nums[i] <= nums[left]){
i += 1 // 从左向右找首个大于基准数的元素
}
// 元素交换
this.swap(nums, i, j) // 交换这两个元素
while(i < j){
while(i < j && nums[j] >= nums[left]){
j -= 1 // 从右向左找首个小于基准数的元素
}
this.swap(nums, i, left) // 将基准数交换至两子数组的分界线
return i // 返回基准数的索引
while(i < j && nums[i] <= nums[left]){
i += 1 // 从左向右找首个大于基准数的元素
}
// 元素交换
this.swap(nums, i, j) // 交换这两个元素
}
this.swap(nums, i, left) // 将基准数交换至两子数组的分界线
return i // 返回基准数的索引
}
/* 快速排序 */
quickSort(nums, left, right){
// 子数组长度为 1 时终止递归
if(left >= right) return
// 哨兵划分
const pivot = this.partition(nums, left, right)
// 递归左子数组、右子数组
this.quickSort(nums, left, pivot - 1)
this.quickSort(nums, pivot + 1, right)
// 子数组长度为 1 时终止递归
if(left >= right) return
// 哨兵划分
const pivot = this.partition(nums, left, right)
// 递归左子数组、右子数组
this.quickSort(nums, left, pivot - 1)
this.quickSort(nums, pivot + 1, right)
}
}
@ -154,4 +154,4 @@ console.log("快速排序（中位基准数优化）完成后 nums =", nums1)
nums2 = [4, 1, 3, 1, 5, 2]
var quickSortTailCall = new QuickSort()
quickSortTailCall.quickSort(nums2, 0, nums2.length - 1)
console.log("快速排序（尾递归优化）完成后 nums =", nums2)
console.log("快速排序（尾递归优化）完成后 nums =", nums2)