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3 changed files with 94 additions and 71 deletions
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@ -987,7 +987,7 @@ status: new
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以上述的求和函数为例,设问题 $f(n) = 1 + 2 + \dots + n$ 。
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- **迭代**:在循环中模拟求和过程,从 $1$ 遍历到 $n$ ,每轮执行求和操作,即可求得 $f(n)$ 。
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- **递归**:将问题分解为子问题 $f(n) = n + f(n-1)$ ,不断(递归地)分解下去,直至基本情况 $f(0) = 0$ 时终止。
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- **递归**:将问题分解为子问题 $f(n) = n + f(n-1)$ ,不断(递归地)分解下去,直至基本情况 $f(1) = 1$ 时终止。
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### 1. 调用栈
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@ -1499,7 +1499,24 @@ status: new
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=== "Swift"
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```swift title="recursion.swift"
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[class]{}-[func]{forLoopRecur}
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/* 使用迭代模拟递归 */
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func forLoopRecur(n: Int) -> Int {
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// 使用一个显式的栈来模拟系统调用栈
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var stack: [Int] = []
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var res = 0
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// 递:递归调用
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for i in stride(from: n, to: 0, by: -1) {
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// 通过“入栈操作”模拟“递”
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stack.append(i)
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}
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// 归:返回结果
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while !stack.isEmpty {
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// 通过“出栈操作”模拟“归”
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res += stack.removeLast()
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}
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// res = 1+2+3+...+n
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return res
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}
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```
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=== "JS"
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@ -155,8 +155,8 @@ $$
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// 初始化 dp 表,用于存储子问题的解
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var dp = Array(repeating: 0, count: n + 1)
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// 初始状态:预设最小子问题的解
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dp[1] = 1
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dp[2] = 2
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dp[1] = cost[1]
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dp[2] = cost[2]
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// 状态转移:从较小子问题逐步求解较大子问题
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for i in stride(from: 3, through: n, by: 1) {
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dp[i] = min(dp[i - 1], dp[i - 2]) + cost[i]
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@ -35,7 +35,7 @@ comments: true
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以下代码给出了链式地址哈希表的简单实现,需要注意两点。
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- 使用列表(动态数组)代替链表,从而简化代码。在这种设定下,哈希表(数组)包含多个桶,每个桶都是一个列表。
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- 以下实现包含哈希表扩容方法。当负载因子超过 $0.75$ 时,我们将哈希表扩容至 $2$ 倍。
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- 以下实现包含哈希表扩容方法。当负载因子超过 $\frac{2}{3}$ 时,我们将哈希表扩容至 $2$ 倍。
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=== "Python"
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@ -47,7 +47,7 @@ comments: true
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"""构造方法"""
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self.size = 0 # 键值对数量
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self.capacity = 4 # 哈希表容量
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self.load_thres = 2 / 3 # 触发扩容的负载因子阈值
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self.load_thres = 2.0 / 3.0 # 触发扩容的负载因子阈值
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self.extend_ratio = 2 # 扩容倍数
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self.buckets = [[] for _ in range(self.capacity)] # 桶数组
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@ -134,7 +134,7 @@ comments: true
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public:
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/* 构造方法 */
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HashMapChaining() : size(0), capacity(4), loadThres(2.0 / 3), extendRatio(2) {
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HashMapChaining() : size(0), capacity(4), loadThres(2.0 / 3.0), extendRatio(2) {
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buckets.resize(capacity);
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}
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@ -253,7 +253,7 @@ comments: true
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public HashMapChaining() {
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size = 0;
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capacity = 4;
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loadThres = 2 / 3.0;
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loadThres = 2.0 / 3.0;
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extendRatio = 2;
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buckets = new ArrayList<>(capacity);
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for (int i = 0; i < capacity; i++) {
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@ -367,7 +367,7 @@ comments: true
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public HashMapChaining() {
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size = 0;
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capacity = 4;
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loadThres = 2 / 3.0;
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loadThres = 2.0 / 3.0;
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extendRatio = 2;
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buckets = new List<List<Pair>>(capacity);
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for (int i = 0; i < capacity; i++) {
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@ -485,7 +485,7 @@ comments: true
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return &hashMapChaining{
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size: 0,
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capacity: 4,
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loadThres: 2 / 3.0,
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loadThres: 2.0 / 3.0,
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extendRatio: 2,
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buckets: buckets,
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}
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@ -606,7 +606,7 @@ comments: true
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init() {
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size = 0
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capacity = 4
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loadThres = 2 / 3
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loadThres = 2.0 / 3.0
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extendRatio = 2
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buckets = Array(repeating: [], count: capacity)
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}
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@ -710,7 +710,7 @@ comments: true
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constructor() {
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this.#size = 0;
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this.#capacity = 4;
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this.#loadThres = 2 / 3.0;
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this.#loadThres = 2.0 / 3.0;
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this.#extendRatio = 2;
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this.#buckets = new Array(this.#capacity).fill(null).map((x) => []);
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}
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@ -818,7 +818,7 @@ comments: true
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constructor() {
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this.#size = 0;
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this.#capacity = 4;
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this.#loadThres = 2 / 3.0;
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this.#loadThres = 2.0 / 3.0;
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this.#extendRatio = 2;
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this.#buckets = new Array(this.#capacity).fill(null).map((x) => []);
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}
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@ -926,7 +926,7 @@ comments: true
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HashMapChaining() {
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size = 0;
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capacity = 4;
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loadThres = 2 / 3.0;
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loadThres = 2.0 / 3.0;
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extendRatio = 2;
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buckets = List.generate(capacity, (_) => []);
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}
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hashmap->capacity = tableSize;
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hashmap->size = 0;
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hashmap->extendRatio = 2;
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hashmap->loadThres = 2.0 / 3;
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hashmap->loadThres = 2.0 / 3.0;
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return hashmap;
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}
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@ -1377,7 +1377,7 @@ comments: true
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"""构造方法"""
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self.size = 0 # 键值对数量
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self.capacity = 4 # 哈希表容量
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self.load_thres = 2 / 3 # 触发扩容的负载因子阈值
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self.load_thres = 2.0 / 3.0 # 触发扩容的负载因子阈值
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self.extend_ratio = 2 # 扩容倍数
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self.buckets: list[Pair | None] = [None] * self.capacity # 桶数组
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self.TOMBSTONE = Pair(-1, "-1") # 删除标记
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@ -1478,7 +1478,7 @@ comments: true
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private:
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int size; // 键值对数量
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int capacity = 4; // 哈希表容量
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const double loadThres = 2.0 / 3; // 触发扩容的负载因子阈值
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const double loadThres = 2.0 / 3.0; // 触发扩容的负载因子阈值
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const int extendRatio = 2; // 扩容倍数
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vector<Pair *> buckets; // 桶数组
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Pair *TOMBSTONE = new Pair(-1, "-1"); // 删除标记
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class HashMapOpenAddressing {
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private int size; // 键值对数量
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private int capacity = 4; // 哈希表容量
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private final double loadThres = 2.0 / 3; // 触发扩容的负载因子阈值
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private final double loadThres = 2.0 / 3.0; // 触发扩容的负载因子阈值
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private final int extendRatio = 2; // 扩容倍数
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private Pair[] buckets; // 桶数组
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private final Pair TOMBSTONE = new Pair(-1, "-1"); // 删除标记
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class HashMapOpenAddressing {
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private int size; // 键值对数量
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private int capacity = 4; // 哈希表容量
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private double loadThres = 2.0 / 3; // 触发扩容的负载因子阈值
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private double loadThres = 2.0 / 3.0; // 触发扩容的负载因子阈值
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private int extendRatio = 2; // 扩容倍数
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private Pair[] buckets; // 桶数组
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private Pair TOMBSTONE = new Pair(-1, "-1"); // 删除标记
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return &hashMapOpenAddressing{
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size: 0,
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capacity: 4,
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loadThres: 2 / 3.0,
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loadThres: 2.0 / 3.0,
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extendRatio: 2,
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buckets: buckets,
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removed: pair{
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var loadThres: Double // 触发扩容的负载因子阈值
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var extendRatio: Int // 扩容倍数
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var buckets: [Pair?] // 桶数组
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var removed: Pair // 删除标记
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var TOMBSTONE: Pair // 删除标记
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/* 构造方法 */
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init() {
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size = 0
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capacity = 4
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loadThres = 2 / 3
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loadThres = 2.0 / 3.0
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extendRatio = 2
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buckets = Array(repeating: nil, count: capacity)
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removed = Pair(key: -1, val: "-1")
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TOMBSTONE = Pair(key: -1, val: "-1")
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}
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/* 哈希函数 */
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Double(size / capacity)
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}
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/* 搜索 key 对应的桶索引 */
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func findBucket(key: Int) -> Int {
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var index = hashFunc(key: key)
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var firstTombstone = -1
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// 线性探测,当遇到空桶时跳出
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while buckets[index] != nil {
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// 若遇到 key ,返回对应桶索引
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if buckets[index]!.key == key {
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// 若之前遇到了删除标记,则将键值对移动至该索引
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if firstTombstone != -1 {
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buckets[firstTombstone] = buckets[index]
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buckets[index] = TOMBSTONE
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return firstTombstone // 返回移动后的桶索引
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}
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return index // 返回桶索引
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}
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// 记录遇到的首个删除标记
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if firstTombstone == -1 && buckets[index] == TOMBSTONE {
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firstTombstone = index
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}
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// 计算桶索引,越过尾部返回头部
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index = (index + 1) % capacity
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}
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// 若 key 不存在,则返回添加点的索引
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return firstTombstone == -1 ? index : firstTombstone
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}
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/* 查询操作 */
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func get(key: Int) -> String? {
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let index = hashFunc(key: key)
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// 线性探测,从 index 开始向后遍历
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for i in stride(from: 0, to: capacity, by: 1) {
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// 计算桶索引,越过尾部返回头部
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let j = (index + i) % capacity
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// 若遇到空桶,说明无此 key ,则返回 nil
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if buckets[j] == nil {
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return nil
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}
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// 若遇到指定 key ,则返回对应 val
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if buckets[j]?.key == key, buckets[j] != removed {
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return buckets[j]?.val
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}
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// 搜索 key 对应的桶索引
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let index = findBucket(key: key)
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// 若找到键值对,则返回对应 val
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if buckets[index] != nil, buckets[index] != TOMBSTONE {
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return buckets[index]!.val
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}
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// 若键值对不存在,则返回 null
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return nil
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}
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if loadFactor() > loadThres {
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extend()
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}
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let index = hashFunc(key: key)
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// 线性探测,从 index 开始向后遍历
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for i in stride(from: 0, through: capacity, by: 1) {
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// 计算桶索引,越过尾部返回头部
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let j = (index + i) % capacity
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// 若遇到空桶、或带有删除标记的桶,则将键值对放入该桶
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if buckets[j] == nil || buckets[j] == removed {
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buckets[j] = Pair(key: key, val: val)
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size += 1
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return
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}
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// 若遇到指定 key ,则更新对应 val
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if buckets[j]?.key == key {
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buckets[j]?.val = val
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return
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}
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// 搜索 key 对应的桶索引
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let index = findBucket(key: key)
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// 若找到键值对,则覆盖 val 并返回
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if buckets[index] != nil, buckets[index] != TOMBSTONE {
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buckets[index]!.val = val
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return
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}
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// 若键值对不存在,则添加该键值对
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buckets[index] = Pair(key: key, val: val)
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size += 1
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}
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/* 删除操作 */
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func remove(key: Int) {
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let index = hashFunc(key: key)
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// 线性探测,从 index 开始向后遍历
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for i in stride(from: 0, to: capacity, by: 1) {
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// 计算桶索引,越过尾部返回头部
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let j = (index + i) % capacity
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// 若遇到空桶,说明无此 key ,则直接返回
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if buckets[j] == nil {
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return
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}
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// 若遇到指定 key ,则标记删除并返回
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if buckets[j]?.key == key {
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buckets[j] = removed
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size -= 1
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return
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}
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// 搜索 key 对应的桶索引
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let index = findBucket(key: key)
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// 若找到键值对,则用删除标记覆盖它
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if buckets[index] != nil, buckets[index] != TOMBSTONE {
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buckets[index] = TOMBSTONE
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size -= 1
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}
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}
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size = 0
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// 将键值对从原哈希表搬运至新哈希表
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for pair in bucketsTmp {
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if let pair, pair != removed {
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if let pair, pair != TOMBSTONE {
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put(key: pair.key, val: pair.val)
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}
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}
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/* 打印哈希表 */
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func print() {
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for pair in buckets {
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if let pair {
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Swift.print("\(pair.key) -> \(pair.val)")
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} else {
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if pair == nil {
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Swift.print("null")
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} else if pair == TOMBSTONE {
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Swift.print("TOMBSTONE")
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} else {
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Swift.print("\(pair!.key) -> \(pair!.val)")
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}
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}
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}
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