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krahets 2023-10-27 01:01:21 +08:00
parent 3628b40f44
commit 5b1a219b8b
4 changed files with 7 additions and 11 deletions
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6
codes/cpp/chapter_tree/array_binary_tree.cpp
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@ -115,9 +115,9 @@ int main() {
int i = 1;
int l = abt.left(i), r = abt.right(i), p = abt.parent(i);
cout << "\n当前节点的索引为 " << i << "，值为 " << abt.val(i) << "\n";
cout << "其左子节点的索引为 " << l << "，值为 " << (l != INT_MAX ? to_string(abt.val(l)) : "None") << "\n";
cout << "其右子节点的索引为 " << r << "，值为 " << (r != INT_MAX ? to_string(abt.val(r)) : "None") << "\n";
cout << "其父节点的索引为 " << p << "，值为 " << (p != INT_MAX ? to_string(abt.val(p)) : "None") << "\n";
cout << "其左子节点的索引为 " << l << "，值为 " << (l != INT_MAX ? to_string(abt.val(l)) : "nullptr") << "\n";
cout << "其右子节点的索引为 " << r << "，值为 " << (r != INT_MAX ? to_string(abt.val(r)) : "nullptr") << "\n";
cout << "其父节点的索引为 " << p << "，值为 " << (p != INT_MAX ? to_string(abt.val(p)) : "nullptr") << "\n";
// 遍历树
vector<int> res = abt.levelOrder();

3
codes/cpp/utils/tree_node.hpp
View file

@ -74,12 +74,11 @@ vector<int> treeToVecor(TreeNode *root) {
return res;
}
/* Free the memory allocated to a tree */
/* 释放二叉树内存 */
void freeMemoryTree(TreeNode *root) {
if (root == nullptr)
return;
freeMemoryTree(root->left);
freeMemoryTree(root->right);
// 释放内存
delete root;
}

4
codes/python/chapter_tree/array_binary_tree.py
View file

@ -92,9 +92,9 @@ if __name__ == "__main__":
arr = [1, 2, 3, 4, None, 6, 7, 8, 9, None, None, 12, None, None, 15]
root = list_to_tree(arr)
print("\n初始化二叉树\n")
print(f"二叉树的数组表示：")
print("二叉树的数组表示：")
print(arr)
print(f"二叉树的链表表示：")
print("二叉树的链表表示：")
print_tree(root)
# 数组表示下的二叉树类

5
docs/chapter_sorting/merge_sort.md
View file

@ -55,10 +55,7 @@
[file]{merge_sort}-[class]{}-[func]{merge_sort}
```
实现合并函数 `merge()` 存在以下难点。
- **需要特别注意各个变量的含义**。`nums` 的待合并区间为 `[left, right]` ，但由于 `tmp` 仅复制了 `nums` 该区间的元素，因此 `tmp` 对应区间为 `[0, right - left]` 。
- 在比较 `tmp[i]` 和 `tmp[j]` 的大小时，**还需考虑子数组遍历完成后的索引越界问题**，即 `i > leftEnd` 和 `j > rightEnd` 的情况。索引越界的优先级是最高的，如果左子数组已经被合并完了，那么不需要继续比较，直接合并右子数组元素即可。
值得注意的是，`nums` 的待合并区间为 `[left, right]` ，而 `tmp` 的对应区间为 `[0, right - left]` 。
## 算法特性