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52 lines
1.7 KiB
Java
52 lines
1.7 KiB
Java
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/**
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* File: build_tree.java
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* Created Time: 2023-07-17
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_divide_and_conquer;
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import utils.*;
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import java.util.*;
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public class build_tree {
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/* 构建二叉树:分治 */
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static TreeNode dfs(int[] preorder, int[] inorder, Map<Integer, Integer> hmap, int i, int l, int r) {
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// 子树区间为空时终止
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if (r - l < 0)
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return null;
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// 初始化根节点
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TreeNode root = new TreeNode(preorder[i]);
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// 查询 m ,从而划分左右子树
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int m = hmap.get(preorder[i]);
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// 子问题:构建左子树
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root.left = dfs(preorder, inorder, hmap, i + 1, l, m - 1);
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// 子问题:构建右子树
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root.right = dfs(preorder, inorder, hmap, i + 1 + m - l, m + 1, r);
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// 返回根节点
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return root;
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}
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/* 构建二叉树 */
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static TreeNode buildTree(int[] preorder, int[] inorder) {
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// 初始化哈希表,存储 inorder 元素到索引的映射
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Map<Integer, Integer> hmap = new HashMap<>();
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for (int i = 0; i < inorder.length; i++) {
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hmap.put(inorder[i], i);
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}
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TreeNode root = dfs(preorder, inorder, hmap, 0, 0, inorder.length - 1);
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return root;
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}
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public static void main(String[] args) {
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int[] preorder = { 3, 9, 2, 1, 7 };
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int[] inorder = { 9, 3, 1, 2, 7 };
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System.out.println("前序遍历 = " + Arrays.toString(preorder));
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System.out.println("中序遍历 = " + Arrays.toString(inorder));
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TreeNode root = buildTree(preorder, inorder);
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System.out.println("构建的二叉树为:");
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PrintUtil.printTree(root);
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}
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}
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