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124 lines
4.4 KiB
Python
124 lines
4.4 KiB
Python
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"""
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File: edit_distancde.py
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Created Time: 2023-07-04
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Author: krahets (krahets@163.com)
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"""
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def edit_distance_dfs(s: str, t: str, i: int, j: int) -> int:
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"""Edit distance: Brute force search"""
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# If both s and t are empty, return 0
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if i == 0 and j == 0:
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return 0
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# If s is empty, return the length of t
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if i == 0:
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return j
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# If t is empty, return the length of s
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if j == 0:
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return i
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# If the two characters are equal, skip these two characters
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if s[i - 1] == t[j - 1]:
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return edit_distance_dfs(s, t, i - 1, j - 1)
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# The minimum number of edits = the minimum number of edits from three operations (insert, remove, replace) + 1
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insert = edit_distance_dfs(s, t, i, j - 1)
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delete = edit_distance_dfs(s, t, i - 1, j)
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replace = edit_distance_dfs(s, t, i - 1, j - 1)
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# Return the minimum number of edits
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return min(insert, delete, replace) + 1
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def edit_distance_dfs_mem(s: str, t: str, mem: list[list[int]], i: int, j: int) -> int:
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"""Edit distance: Memoized search"""
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# If both s and t are empty, return 0
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if i == 0 and j == 0:
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return 0
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# If s is empty, return the length of t
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if i == 0:
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return j
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# If t is empty, return the length of s
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if j == 0:
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return i
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# If there is a record, return it
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if mem[i][j] != -1:
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return mem[i][j]
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# If the two characters are equal, skip these two characters
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if s[i - 1] == t[j - 1]:
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return edit_distance_dfs_mem(s, t, mem, i - 1, j - 1)
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# The minimum number of edits = the minimum number of edits from three operations (insert, remove, replace) + 1
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insert = edit_distance_dfs_mem(s, t, mem, i, j - 1)
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delete = edit_distance_dfs_mem(s, t, mem, i - 1, j)
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replace = edit_distance_dfs_mem(s, t, mem, i - 1, j - 1)
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# Record and return the minimum number of edits
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mem[i][j] = min(insert, delete, replace) + 1
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return mem[i][j]
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def edit_distance_dp(s: str, t: str) -> int:
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"""Edit distance: Dynamic programming"""
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n, m = len(s), len(t)
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dp = [[0] * (m + 1) for _ in range(n + 1)]
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# State transition: first row and first column
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for i in range(1, n + 1):
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dp[i][0] = i
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for j in range(1, m + 1):
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dp[0][j] = j
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# State transition: the rest of the rows and columns
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for i in range(1, n + 1):
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for j in range(1, m + 1):
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if s[i - 1] == t[j - 1]:
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# If the two characters are equal, skip these two characters
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dp[i][j] = dp[i - 1][j - 1]
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else:
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# The minimum number of edits = the minimum number of edits from three operations (insert, remove, replace) + 1
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dp[i][j] = min(dp[i][j - 1], dp[i - 1][j], dp[i - 1][j - 1]) + 1
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return dp[n][m]
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def edit_distance_dp_comp(s: str, t: str) -> int:
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"""Edit distance: Space-optimized dynamic programming"""
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n, m = len(s), len(t)
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dp = [0] * (m + 1)
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# State transition: first row
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for j in range(1, m + 1):
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dp[j] = j
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# State transition: the rest of the rows
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for i in range(1, n + 1):
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# State transition: first column
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leftup = dp[0] # Temporarily store dp[i-1, j-1]
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dp[0] += 1
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# State transition: the rest of the columns
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for j in range(1, m + 1):
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temp = dp[j]
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if s[i - 1] == t[j - 1]:
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# If the two characters are equal, skip these two characters
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dp[j] = leftup
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else:
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# The minimum number of edits = the minimum number of edits from three operations (insert, remove, replace) + 1
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dp[j] = min(dp[j - 1], dp[j], leftup) + 1
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leftup = temp # Update for the next round of dp[i-1, j-1]
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return dp[m]
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"""Driver Code"""
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if __name__ == "__main__":
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s = "bag"
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t = "pack"
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n, m = len(s), len(t)
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# Brute force search
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res = edit_distance_dfs(s, t, n, m)
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print(f"To change {s} to {t}, the minimum number of edits required is {res}")
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# Memoized search
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mem = [[-1] * (m + 1) for _ in range(n + 1)]
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res = edit_distance_dfs_mem(s, t, mem, n, m)
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print(f"To change {s} to {t}, the minimum number of edits required is {res}")
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# Dynamic programming
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res = edit_distance_dp(s, t)
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print(f"To change {s} to {t}, the minimum number of edits required is {res}")
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# Space-optimized dynamic programming
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res = edit_distance_dp_comp(s, t)
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print(f"To change {s} to {t}, the minimum number of edits required is {res}")
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