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59 lines
1.5 KiB
JavaScript
59 lines
1.5 KiB
JavaScript
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/**
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* File: top_k.js
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* Created Time: 2023-08-13
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* Author: Justin (xiefahit@gmail.com)
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*/
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const { MaxHeap } = require('./my_heap');
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/* 元素入堆積 */
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function pushMinHeap(maxHeap, val) {
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// 元素取反
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maxHeap.push(-val);
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}
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/* 元素出堆積 */
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function popMinHeap(maxHeap) {
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// 元素取反
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return -maxHeap.pop();
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}
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/* 訪問堆積頂元素 */
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function peekMinHeap(maxHeap) {
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// 元素取反
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return -maxHeap.peek();
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}
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/* 取出堆積中元素 */
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function getMinHeap(maxHeap) {
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// 元素取反
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return maxHeap.getMaxHeap().map((num) => -num);
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}
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/* 基於堆積查詢陣列中最大的 k 個元素 */
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function topKHeap(nums, k) {
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// 初始化小頂堆積
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// 請注意:我們將堆積中所有元素取反,從而用大頂堆積來模擬小頂堆積
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const maxHeap = new MaxHeap([]);
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// 將陣列的前 k 個元素入堆積
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for (let i = 0; i < k; i++) {
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pushMinHeap(maxHeap, nums[i]);
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}
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// 從第 k+1 個元素開始,保持堆積的長度為 k
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for (let i = k; i < nums.length; i++) {
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// 若當前元素大於堆積頂元素,則將堆積頂元素出堆積、當前元素入堆積
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if (nums[i] > peekMinHeap(maxHeap)) {
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popMinHeap(maxHeap);
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pushMinHeap(maxHeap, nums[i]);
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}
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}
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// 返回堆積中元素
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return getMinHeap(maxHeap);
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}
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/* Driver Code */
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const nums = [1, 7, 6, 3, 2];
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const k = 3;
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const res = topKHeap(nums, k);
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console.log(`最大的 ${k} 個元素為`, res);
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